regex - egrep 匹配多行

Question

我在多个主机上有多个 Apache vHost 配置。我正在尝试编写一个 Bash 脚本，它将遍历每个主机并搜索 .conf每个文件，拉出第一个(只有第一个)<VirtualHost>堵塞。我试过写一个正则表达式来匹配它，但它不起作用。这是我试过的代码:

    #!/bin/bash
    egrep -o '(\<VirtualHost\>)(.*)(\<\/VirtualHost\>)' -m1

自 .*不匹配换行符，我什至试过这个:

    #!/bin/bash
    egrep -o '(\<VirtualHost\>)(.*[\S]*)(\<\/VirtualHost\>)' -m1

我还是一无所获。 :-(

我不明白我在这里做错了什么。这是我尝试匹配的数据示例:

    <VirtualHost apache-frontend:80>
            ServerAdmin     mysite@domain.com
            ServerName      domain.com
            DocumentRoot    /path/to/my/doc/root

            RewriteEngine   On
            Include         include.d/global/rewrite.conf
            RewriteRule     ^(.*)$ http://www.domain.com$1 [R=301,L]
    </VirtualHost>

    <VirtualHost apache-frontend:80>
            ServerAdmin     mysite@domain.com
            ServerName      domain.com
            DocumentRoot    /path/to/my/doc/root

            RewriteEngine   On
            Include         include.d/global/rewrite.conf
            RewriteRule     ^(.*)$ http://www.domain.com$1 [R=301,L]
    </VirtualHost>

    <VirtualHost apache-frontend:80>
            ServerAdmin     mysite@domain.com
            ServerName      domain.com
            DocumentRoot    /path/to/my/doc/root

            RewriteEngine   On
            Include         include.d/global/rewrite.conf
            RewriteRule     ^(.*)$ http://www.domain.com$1 [R=301,L]
    </VirtualHost>

Answer 1

这个 oneliner 只从配置文件中提取第一个 VirtualHost block :

awk '/<VirtualHost/,/<\/VirtualHost>/{print $0} /<\/VirtualHost>/{exit}' < vhostconf