bash - zsh 循环遍历多个参数

Question

在我的旧 .bashrc 中，我有一个简短的部分如下:

PATH2ADD_SCRIPTBIN="/home/foo/bar/scriptbin"
PATH2ADD_PYTHONSTUFF="/home/foo/bar/pythonprojects"

PATH2ADDLIST="$PATH2ADD_SCRIPTBIN $PATH2ADD_PYTHONSTUFF"

for PATH2ADD in $PATH2ADDLIST; do

    if [ -z `echo $PATH | grep "$PATH2ADD"` ]; then

        export PATH=$PATH:$PATH2ADD
        echo "Added '$PATH2ADD' to the PATH."

    fi

done

在 Bash 中，这按预期工作:它附加了我在 $PATH2ADDLIST 中包含的路径，如果它们还没有出现在路径中(我必须在意识到我的路径有多大之后这样做每次我采购我的 .bashrc 时都会收到)。输出(当提供的路径不存在时)如下:

Added '/home/foo/bar/scriptbin' to the PATH.
Added '/home/foo/bar/pythonprojects' to the PATH.

但是，我最近切换到了神奇的 Zsh 领域，现在完全相同的文本行产生了这个结果:

Added '/home/foo/bar/scriptbin /home/foo/bar/pythonprojects' to the PATH.

现在我很确定这是因为 Zsh 进行参数扩展的方式有些不同，或者它与 Zsh 改变 的方式有关code>for 循环，但我不确定如何解决这个问题。

可能有人有一些见解吗？

Answer 1

使用数组来存储这些变量，即

PATH2ADD_SCRIPTBIN="/home/foo/bar/scriptbin"
PATH2ADD_PYTHONSTUFF="/home/foo/bar/pythonprojects"

# Initializing 'PATH2ADDLIST' as an array with the 2 variables
# to make the looping easier

PATH2ADDLIST=("${PATH2ADD_SCRIPTBIN}" "${PATH2ADD_PYTHONSTUFF}")

# Looping through the array contents
for PATH2ADD in "${PATH2ADDLIST[@]}"
do 
    # Using the exit code of 'grep' directly with a '!' negate
    # condition
    if ! echo "$PATH" |  grep -q "$PATH2ADD"
    then
        export PATH=$PATH:$PATH2ADD
        echo "Added '$PATH2ADD' to the PATH."
    fi
done

这样可以使它在 zsh 和 bash 中更加兼容。在两个 shell 上进行示例试运行，

# With interpreter set to /bin/zsh

zsh script.sh 
Added '/home/foo/bar/scriptbin' to the PATH.
Added '/home/foo/bar/pythonprojects' to the PATH.

并在 bash

中

bash script.sh 
Added '/home/foo/bar/scriptbin' to the PATH.
Added '/home/foo/bar/pythonprojects' to the PATH.