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bash - 在 bash 中解析输出

转载 作者:行者123 更新时间:2023-11-29 09:38:00 25 4
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    //
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所以在第一行之后,每一行都以括号中的数字开头。我需要对括号中的数字进行 grep 并将其输出到一个新文件中(不带 [) ..如何完成>

最佳答案

grep -Po '(?<=\[)\d+(?=\])' file > new_file

-P对于 Perl 正则表达式,因此可以使用:

  • \d一个数字
  • 正后视正前视((?<=\[)(?=\]))

-o 仅匹配

关于bash - 在 bash 中解析输出,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29877666/

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