java - Libgdx - 从 Rectangle.overlap(Rectangle) 获取相交矩形

Question

有没有办法知道 libgdx 中两个 Rectangle 之间的交集 Rectangle 面积，就像 C# 中的 Rectangle http://msdn.microsoft.com/en-us/library/microsoft.xna.framework.rectangle.intersect.aspx ？

我需要获取两个矩形之间的交集矩形区域，但是 libgdx 中的重叠方法只返回 boolean 值，无论两个矩形是否相交。我已经阅读了 Intersector 类，但它没有提供任何相关内容。

Answer 1

事实上，LibGDX 并没有内置这个功能，所以我会这样做:

/** Determines whether the supplied rectangles intersect and, if they do,
 *  sets the supplied {@code intersection} rectangle to the area of overlap.
 * 
 * @return whether the rectangles intersect
 */
static public boolean intersect(Rectangle rectangle1, Rectangle rectangle2, Rectangle intersection) {
    if (rectangle1.overlaps(rectangle2)) {
        intersection.x = Math.max(rectangle1.x, rectangle2.x);
        intersection.width = Math.min(rectangle1.x + rectangle1.width, rectangle2.x + rectangle2.width) - intersection.x;
        intersection.y = Math.max(rectangle1.y, rectangle2.y);
        intersection.height = Math.min(rectangle1.y + rectangle1.height, rectangle2.y + rectangle2.height) - intersection.y;
        return true;
    }
    return false;
}