javascript - 消息: count(): Parameter must be an array or an object that implements Countable in codeigniter model

Question

我有模型查询，但收到错误消息:count(): 参数必须是在某些系统中实现 Countable 的数组或对象，并且在某些系统中其工作正常。这是查询我遇到了问题。

     public function getChatPlanProvidersInfoById($planId) {
    $providersArr = array();
    $this->db->select('ppm.price as plan_price, ppm.offer_start, ppm.offer_end, ppm.validity_period, pipm.provider_id, pipm.provider_group_id');
    $this->db->from('chatinstance_provider_mapping pipm');
    $this->db->join('chatplan_instance ppm', 'ppm.id = pipm.chatplan_instance_id');
    $this->db->where('pipm.chatplan_instance_id', $planId);
    $query = $this->db->get();
    if ($query->num_rows() > 0) {
        $providersInfo = $query->result();
        if (count($providersInfo) > 0) {
            $providersArr['offerInfo'] = array('offer_start' => $providersInfo[0]->offer_start, 'offer_end' => $providersInfo[0]->offer_end, 'valid_period' => $providersInfo[0]->validity_period);
            $providersArr['plan_price'] = $providersInfo[0]->plan_price;
            foreach ($providersInfo as $provider) {
                if (!empty($provider->provider_id)) {
                    $pInfo = $this->getProviderInfoById($provider->provider_id);
                    $providersArr['providerInfo'][] = $pInfo;
                } else if (!empty($provider->provider_group_id)) {
                    $pInfo = $this->getProviderGroupInfoById($provider->provider_group_id);
                    if (count($pInfo) > 0) {
                        $providersArr['providerInfo'][] = $pInfo;
                    } else {
                        $providersArr['providerInfo'][] = array();
                    }
                }
            }
        }
    }
    return $providersArr;
}

在此 if 条件 count($pInfo) 中出现错误

                   if (count($pInfo) > 0) {
                        $providersArr['providerInfo'][] = $pInfo;
                    } else {
                        $providersArr['providerInfo'][] = array();
                    }

Answer 1

它在您的系统上运行的原因可能是您使用的是PHP版本5.6或<7.2

与版本 7.2 一样，如果将 null 或 false 传递给 count()，您将收到警告

$data[5]  = 7;
var_dump(count($data)); // It will return 1


var_dump(count(null)); // It will give Warning: count(): Parameter must be an array or an object that implements Countable in...

var_dump(count(false)); // It will give Warning: count(): Parameter must be an array or an object that implements Countable in...

所以在你的情况

您应该在传递给 count() 之前检查 $pInfo，如下所示

if ($pInfo && count($pInfo) > 0) {...