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mysql - "How to query this in mysql? I am getting nowhere."

转载 作者:行者123 更新时间:2023-11-29 09:32:32 25 4
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我想将所有具有不同值的列放在右侧。谢谢。

(Column name as follows)
ID
Course
Year Level
Birthdate
Academic ID
Academic Year
Subject
Units
Grade

1900000 | BSIS | 1st Year | 1997-10-08 | 2019-2020-1st Semester | MATH | 3 | 2.0

1900000 | BSIS | 1st Year | 1997-10-08 | 2018-2019-1st Semester | ENG 1 | 3 | 2.1

1900000 | BSIS | 1st Year | 1997-10-08 | 2019-2020-1st Semester | FIL 1 | 3 | 2.0

1900000 | BSIS | 1st Year | 1997-10-08 | 2019-2020-2nd Semester | FIL 1 | 3 | 3.0

1900000 | BSIS | 1st Year | 1997-10-08 | 2018-2019-1st Semester | FIL 1 | 3 | 2.0

尽我所能。拿不到。

输出:到一行(2019-2020-第一学期)

(Column name as follows)
ID
Course
Year Level
Birthdate
Academic ID
Academic Year
Subject
Units
Grade
Subject2
Units
Grade
Subject3
Units
Grade
.......

1900000 | BSIS | 1st Year | 1997-10-08 | 2019-2020-1st Semester | MATH | 3 | 2.0 | MATH | 3 | 2.0 | ENG 1 | 3 | 2.0 | FIL 1 | 3 | 2.0 |

最佳答案

这应该是直截了当的,不需要动态列和旋转,因为主题很少。

  1. select unique ID using distinct() keyword.
  2. join each subjects based on ID
select t1.ID, t1.Course, t1."Year Level", t1.Birthdate, t1."Academic ID", t1."Academic Year"
,m.Subject, m.Units, m.Grade
,e.Subject, e.Units, e.Grade
,e.Subject, e.Units, e.Grade
from
(select distinct ID, Course, "Year Level", Birthdate, "Academic ID", "Academic Year" from tableA) as t1
left join tableA m on Subject = 'MATH' and m.ID = t1.ID
left join tableA e on Subject = 'ENG 1' and e.ID = t1.ID
left join tableA f on Subject = 'FIL 1' and f.ID = t1.ID

关于mysql - "How to query this in mysql? I am getting nowhere.",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58386964/

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