bash - 在 bash 中包含以空格开头的换行符？

Question

所以，文本文件是这样的:

TITLE and AUTHOR                                                     ETEXT NO.

Aspects of plant life; with special reference to the British flora,      56900
 by Robert Lloyd Praeger

The Vicar of Morwenstow, by Sabine Baring-Gould                          56899
 [Subtitle: Being a Life of Robert Stephen Hawker, M.A.]

Raamatun tutkisteluja IV, mennessä Charles T. Russell                    56898
 [Subtitle: Harmagedonin taistelu]
 [Language: Finnish]

Raamatun tutkisteluja III, mennessä Charles T. Russell                   56897
 [Subtitle: Tulkoon valtakuntasi]
 [Language: Finnish]

文件名为 GUTINDEX.ALL。

我想在文件中搜索字符串。当它找到时，它应该打印整个记录。

所以我这样做了:

#!/bin/sh
read -p 'string to search ' searchstring
grep --color "$searchstring" GUTINDEX.ALL

当我搜索字符串“flora”时它打印

Aspects of plant life; with special reference to the British flora,    56900

但如果新行以空格开头，我也想打印它。像这样:

Aspects of plant life; with special reference to the British flora,   56900

 by Robert Lloyd Praeger

Answer 1

首先阅读整个记录然后进行搜索。需要在文件末尾换行:

sed -n ':l N;/^$/!tl;/'"$searchstring"'/p' input