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php - 无法使用 URL 中的新值更新 MYSQL 数据库(使用 GET)

转载 作者:行者123 更新时间:2023-11-29 09:27:48 25 4
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我需要我的数据库根据从 url 获取的变量来更新“SID”行。

现在,如果我有这样的链接:http://localhost/index.php?sid=fdskdsfkl202klfdfkldsfsdlk2

它将在 SID 输入字段中显示:fdskdsfkl202klfdfkldsfsdlk2

但是当我按注册时,它总是在数据库中显示:“NoSidAttached”。

我在代码中遗漏了一些内容,但找不到什么...

注册页面的完整代码,包括 HTML 和 PHP。

<?php
// Initialize the session
session_start();

// Check if the user is already logged in, if yes then redirect him to welcome page
if(isset($_SESSION["loggedin"]) && $_SESSION["loggedin"] === true){
header("location: welcome.php");
exit;
}

// Include config file
require_once "config.php";

// Define variable sID from URL
if(isset($_GET['sid'])) {
$sid = $_GET['sid'];
} else {
$sid = 'NoSidAttached';
}

// Define variables and initialize with empty values
$username = $password = $confirm_password = "";
$username_err = $password_err = $confirm_password_err = "";

// Processing form data when form is submitted
if($_SERVER["REQUEST_METHOD"] == "POST"){

// Validate username
if(empty(trim($_POST["username"]))){
$username_err = "Please enter a username.";
} else{
// Prepare a select statement
$sql = "SELECT id FROM users WHERE username = ?";

if($stmt = mysqli_prepare($link, $sql)){
// Bind variables to the prepared statement as parameters
mysqli_stmt_bind_param($stmt, "s", $param_username);

// Set parameters
$param_username = trim($_POST["username"]);

// Attempt to execute the prepared statement
if(mysqli_stmt_execute($stmt)){
/* store result */
mysqli_stmt_store_result($stmt);

if(mysqli_stmt_num_rows($stmt) == 1){
$username_err = "This username is already taken.";
} else{
$username = trim($_POST["username"]);
}
} else{
echo "Oops! Something went wrong. Please try again later.";
}
}

// Close statement
mysqli_stmt_close($stmt);
}

// Validate password
if(empty(trim($_POST["password"]))){
$password_err = "Please enter a password.";
} elseif(strlen(trim($_POST["password"])) < 6){
$password_err = "Password must have atleast 6 characters.";
} else{
$password = trim($_POST["password"]);
}

// Validate confirm password
if(empty(trim($_POST["confirm_password"]))){
$confirm_password_err = "Please confirm password.";
} else{
$confirm_password = trim($_POST["confirm_password"]);
if(empty($password_err) && ($password != $confirm_password)){
$confirm_password_err = "Password did not match.";
}
}

// Check input errors before inserting in database
if(empty($username_err) && empty($password_err) && empty($confirm_password_err)){

// Prepare an insert statement
$sql = "INSERT INTO users (username, password, sid) VALUES (?, ?, ?)";

if($stmt = mysqli_prepare($link, $sql)){
// Bind variables to the prepared statement as parameters
mysqli_stmt_bind_param($stmt, "sss", $param_username, $param_password, $param_sid);

// Set parameters
$param_sid = $sid;
$param_username = $username;
$param_password = password_hash($password, PASSWORD_DEFAULT); // Creates a password hash

// Attempt to execute the prepared statement
if(mysqli_stmt_execute($stmt)){
session_start();

// Store data in session variables
$_SESSION["loggedin"] = true;
$_SESSION["id"] = $id;
$_SESSION["username"] = $username;
header("location: welcome.php");
} else{
echo "Something went wrong. Please try again later.";
}
}

// Close statement
mysqli_stmt_close($stmt);
}

// Close connection
mysqli_close($link);
}
?>

<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Sign Up</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.css">
<style type="text/css">
body{ font: 14px sans-serif; }
.wrapper{ width: 350px; padding: 20px; }
</style>
</head>
<body>
<div class="wrapper">
<h2>Sign Up</h2>
<p>Please fill this form to create an account.</p>
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">
<div class="form-group <?php echo (!empty($username_err)) ? 'has-error' : ''; ?>">
<label>Username</label>
<input type="text" name="username" class="form-control" value="<?php echo $username; ?>">
<span class="help-block"><?php echo $username_err; ?></span>
</div>
<div class="form-group <?php echo (!empty($password_err)) ? 'has-error' : ''; ?>">
<label>Password</label>
<input type="password" name="password" class="form-control" value="<?php echo $password; ?>">
<span class="help-block"><?php echo $password_err; ?></span>
</div>
<div class="form-group <?php echo (!empty($confirm_password_err)) ? 'has-error' : ''; ?>">
<label>Confirm Password</label>
<input type="password" name="confirm_password" class="form-control" value="<?php echo $confirm_password; ?>">
<span class="help-block"><?php echo $confirm_password_err; ?></span>
</div>
<div class="form-group">
<label>SID</label>
<input type="text" name="sid" class="form-control" value="<?php echo $sid; ?>">
</div>
<div class="form-group">
<input type="submit" class="btn btn-primary" value="Submit">
<input type="reset" class="btn btn-default" value="Reset">
</div>
<p>Already have an account? <a href="login.php">Login here</a>.</p>
</form>
</div>
</body>
</html>

最佳答案

        <form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">

您的表单使用method="post",这意味着在本例中“sid”将位于 $_POST 中。正如评论中提到的,$_REQUEST 作为 $_GET、$_POST、$_COOKIE 的组合是涵盖这两种情况的最佳方法。或者将表单的方法改为“get”。

还有一件事:

            if(mysqli_stmt_execute($stmt)){
session_start();

请去掉第二个session_start()。 session 在任何输出发生之前启动(您已经在文件开头正确执行了此操作),后续的 session_start 不执行任何操作。

关于php - 无法使用 URL 中的新值更新 MYSQL 数据库(使用 GET),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59285430/

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