linux - 用适当数量的 "*"替换偶数词

Question

我需要输入一些行数，用适当数量的“*”替换偶数行上的所有单词并将结果输出到屏幕。

例如输入:

Hi! How are you? 

It's been a while since we've met.

会给我们:

Hi! *** are ****

It's **** a ***** since ***** met.

这是我尝试过的:

#!/bin/bash

res=""

mm="*"

i=0

while IFS= read -r line; do 

for word in line

do

tmp=""

lng=${#word}

if [ $(($lng % 2)) -eq 0 ]; 

then

while [ $i -lt $lng ]; do

tmp=$tmp$mm

let i=i+1

done

res+=${tmp}

else

res+=${word}

fi

done

done

echo -e "${res}"

但是它并没有做它应该做的事情(

有什么建议吗？

Answer 1

作为 perl 的一行代码:

$ echo "Hi! How are you?\nIt's been a while since we've met." \
   | perl -pe 's/\S+\s+\K(\S+)/"*" x length($1)/eg'
Hi! *** are ****
It's **** a ***** since ***** met.

基本上，对于每对由空格分隔的单词，用与其长度相等的星号替换第二个单词。