mysql - 在 Mysql 中检索 JSON 数组内的 Json 数据值

Question

我有 JSON 列，其中包含 JSON 数组。我的场景是获取 url 值为的所有记录'"example.com/user1"' 存在。我在编写此操作的查询时遇到问题。

Record1
 [
    {
        "id": "1",
        "firstname": "user1",
        "url": "example.com/user1"
    },
    {
        "id": "2",
        "firstname": "user2",
        "url": "example.com/user2"
    }
]
Record2
     [
        {
            "id": "1",
            "firstname": "user3",
            "url": "example.com/user3"
        },
        {
            "id": "2",
            "firstname": "user2",
            "url": "example.com/user2"
        }
    ]
......
......
......
Record10
     [
        {
            "id": "1",
            "firstname": "user10",
            "url": "example.com/user10"
        },
        {
            "id": "2",
            "firstname": "user1",
            "url": "example.com/user1"
        }
    ]

我运行的查询是:

Select internal_id from users_dummy where JSON_EXTRACT(user_friends, '$[0].url') = "example.com/user1" or JSON_EXTRACT(user_friends, '$[1].url') = "example.com/user1";

所以o/p是:记录1，记录10

这是在记录中搜索值的正确方法吗？提前致谢。

Answer 1

您可以使用JSON_SEARCH像这样:

SELECT * 
FROM users_dummy 
WHERE JSON_SEARCH(user_friends, 'one', 'example.com/user1', NULL, '$[*].url') IS NOT NULL

demo on dbfiddle.uk

如果您使用对象而不是数组，可以使用以下解决方案:

SELECT * 
FROM users_dummy 
WHERE JSON_SEARCH(user_friends, 'one', 'example.com/user1', NULL, '$.*.url') IS NOT NULL

demo on dbfiddle.uk