bash - 展平目录结构并保留重复文件

Question

我的目录结构如下所示:

foo
├── 1.txt
├── 2.txt
├── 3.txt
├── 4.txt
└── bar
    ├── 1.txt
    ├── 2.txt
    └── 5.txt

我想展平这个目录结构，以便所有文件都在 foo 目录中并保留重复文件:

foo
├── 1.txt
├── 2.txt
├── 3.txt
├── 4.txt
├── bar-1.txt
├── bar-2.txt
└── bar-5.txt

重命名的重复文件名无关紧要。

我可以使用简单的 Unix 单行代码或简单的 shell 脚本来执行此操作吗？

Answer 1

这应该有效:

target="/tmp/target"; find . -type f | while read line; do outbn="$(basename "$line")"; while true; do if [[ -e "$target/$outbn" ]]; then outbn="z-$outbn"; else break; fi; done; cp "$line" "$target/$outbn"; done

格式化为非一行:

target="/tmp/target"
find . -type f | while read line; do
  outbn="$(basename "$line")"
  while true; do
    if [[ -e "$target/$outbn" ]]; then
      outbn="z-$outbn"
    else
      break
    fi
  done
  cp "$line" "$target/$outbn"
done

一定要在你的案例中从 foo 目录运行它，并将 $target 变量设置为目标目录。

例子:

$ find foofoofoo/1foo/2foo/3foo/4foo/barfoo/bar/1foo/bar/2foo/bar/3foo/bar/4foo/bar/5

$ cd foo/
$ target="/tmp/target"; find . -type f | while read line; do outbn="$(basename "$line")"; while true; do if [[ -e "$target/$outbn" ]]; then outbn="z-$outbn"; else break; fi; done; cp "$line" "$target/$outbn"; done

然后

$ find $target/tmp/target/tmp/target/1/tmp/target/2/tmp/target/3/tmp/target/4/tmp/target/5/tmp/target/z-1/tmp/target/z-2/tmp/target/z-3/tmp/target/z-4