bash - 创建多个目录的 Shell 脚本

Question

我正在尝试创建一个文件层次结构来存储数据。我想为每个数据采集 session 创建一个文件夹。该文件夹有五个子文件夹，名称如下。我在下面的代码尝试给出了一个错误，但我不确定如何更正它。

代码

 #!/bin/sh
 TRACES = "/Traces"
 LFPS = '/LFPS'
 ANALYSIS = '/Analysis' 
 NOTES = '/Notes'
 SPIKES = '/Spikes'

 folders=($TRACES $LFPS $ANALYSIS $NOTES $SPIKES)
 for folder in "${folders[@]}"
  do
    mkdir $folder
  done

错误声明变量时出现错误。如上所述，bash 翻转错误 Command not found。相反，如果我将文件名声明为 TRACES = $('\Traces')，bash 将翻转错误 No such file or directory .

Answer 1

去掉变量名和值之间的空格:

#!/bin/sh
TRACES="/Traces"
LFPS='/LFPS'
ANALYSIS='/Analysis' 
NOTES='/Notes'
SPIKES='/Spikes'

folders=($TRACES $LFPS $ANALYSIS $NOTES $SPIKES)
for folder in "${folders[@]}"
 do
   mkdir $folder
 done

对于空格，bash 解释为

COMMAND param1 param2

以=作为param1