mysql - 找不到丢失的表别名

Question

我收到错误:每个派生表必须有自己的别名但我看不到丢失的别名在哪里。你能帮我找到它吗？

select *
from 
    (select distinct brand.industry, cur.subindustry, brand.brand, dims.activity, dims.detail, cur.referral_source
    from 
        referraldb.report_referral_db_viz_qa cur
        inner join referraldb.report_referral_db_viz_qa prv 
            on cur.report_time_id = prv.report_time_id 
                and cur.dimension_id = prv.dimension_id 
                and cur.brand_id = prv.brand_id 
                and cur.referral_source = prv.referral_source
                and cur.date = date_add(LAST_DAY(DATE_SUB(@d, INTERVAL 1 month)), interval 1 day) 
                and prv.date = date_add(LAST_DAY(DATE_SUB(@d, INTERVAL 2 month)), interval 1 day)
        inner join referraldb.dim_all_dimensions dims
            on dims.dimension_id = prv.dimension_id
        inner join referraldb.dim_brand brand  
            on brand.brand_id = prv.brand_id
    where 
        dims.lag = 'immediate' 
        and dims.measure_type = 'visits'
        and prv.subindustry = 'flight' 
        and prv.report_time_id = 1 
        and abs((((cur.current_test - prv.current_test)/cur.current_test) * 100)) >= 30)) a
inner join
(select  fact.referral_source, brand.Industry, fact.subindustry,  brand.Brand, dims.Activity, dims.Detail
    from 
        referraldb.report_referral_db_viz_qa fact inner join
        referraldb.dim_brand brand
            on brand.brand_id = fact.brand_id inner join
        referraldb.dim_report_time t
            on t.report_time_id = fact.report_time_id inner join
        referraldb.dim_all_dimensions dims
             on dims.dimension_id = fact.dimension_id         
    where dims.lag = 'Immediate' and dims.measure_type = 'Visits' and fact.subindustry = 'flight' and fact.report_time_id = 1 and fact.date > DATE_SUB(NOW(), INTERVAL 14 month)
    group by fact.referral_source, brand.Industry, fact.Subindustry,  brand.Brand, dims.Activity, dims.Detail 
    having avg(current_test) > 200000 ) as b    
on a.industry = b.industry and a.subindustry = b.subindustry and a.brand = b.brand and a.activity = b.activity and a.detail = b.detail and a.referral_source = b.referral_source 

Answer 1

这行不应该

having avg(current_test) > 200000 ) as b  

是

 having avg(current_test) > 200000 ) b

还有一个右括号太多(或者一个左括号太少)。第一个与该行中最后一个之前的匹配:

and abs((((cur.current_test - prv.current_test)/cur.current_test) * 100)) >= 30)) a