regex - bash 比较字符串与字符串列表

Question

假设我在 bash 中有以下代码:

#!/bin/bash

bad_fruit=( apple banana kiwi )
for fname in `ls`
do
  # want to check if fname contains one of the bad_fruit
  is_bad_fruit=??? # <------- fix this line
  if [ is_bad_fruit ]
  then
    echo "$fname contains bad fruit in its name"
  else
    echo "$fname is ok"
  fi
done

如何修复 is_bad_fruit 以便在 fname 包含 bad_fruit 字符串之一时为真？

Answer 1

试试下面的代码:

#!/bin/bash

bad_fruit=( apple banana kiwi )
re="$(printf '%s\n' "${bad_fruit[@]}" | paste -sd '|')"

for fname in *; do
  # want to check if fname contains one of the bad_fruit
  if [[ $fname =~ $re ]]; then
    echo "$fname contains bad fruit in its name"
  else
    echo "$fname is ok"
  fi
done

照顾useless use of ls

ls 是一种用于交互式查看文件信息的工具。它的输出是为人类格式化的，会导致脚本中的错误。使用 glob 或 find 代替。明白为什么:http://mywiki.wooledge.org/ParsingLs