bash - 在 Bash 中使用空格

Question

我需要找到在 case 模式中使用空格的解决方案。我有这个功能 case

  setParam() {
    case "$1" in
          0624)
            # do something - download file from url
          ;;
          del-0624)
            # do something - delete file from local machine
            exit 0
          ;;
      # Help
          *|''|h|help)
            printHelp
            exit 0
          ;;
    esac
  }

  for PARAM in $*; do
    setParam "$PARAM"
  done

Paramter "0624" 用于从 url 下载文件的运行函数。参数"del-0624"用于删除 native 文件。

问题:可以使用参数"del 0624"(带空格)吗？我在 case 中的参数空间有问题。

Answer 1

在case 中需要使用双引号。此外，脚本应作为 ./script "del 0624" 运行。

setParam() {
    case "$1" in
          "0624")
            # do something - download file from url
          ;;
          "del-0624")
            # do something - delete file from local machine
            exit 0
          ;;
          "del 0624")
            # do something - delete file from local machine
            exit 0
          ;;
      # Help
          *|''|h|help)
            printHelp
            exit 0
          ;;
    esac
  }