bash - 如何通过在 bash 脚本中输入两次来安全地确认密码

Question

我想创建一个 bash 脚本，用户可以在其中选择用户名、密码并通过输入两次来确认密码。如果密码不匹配，应提示用户再次输入。如果密码匹配，脚本应该创建一个密码哈希，否则再次询问直到正确为止。

到目前为止，我有下面的代码，但我不确定这是否是正确的方法。下面的 bash 脚本有问题吗？

# read username
read -p "Username: " username

# read password twice
read -s -p "Password: " password
echo 
read -s -p "Password (again): " password2

# check if passwords match and if not ask again
while [ "$password" != "$password2" ];
do
    echo 
    echo "Please try again"
    read -s -p "Password: " password
    echo
    read -s -p "Password (again): " password2
done

# create passwordhash
passwordhash=`openssl passwd -1 $password`

# do something with the user and passwordhash

Answer 1

一种减少冗长的方法:

#!/bin/bash
   
read -p "Username: " username
while true; do
  read -s -p "Password: " password
  echo
  read -s -p "Password (again): " password2
  echo
  [ "$password" = "$password2" ] && break
  echo "Please try again"
done