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java - 如何在java中的套接字之间传递音频

转载 作者:行者123 更新时间:2023-11-29 09:06:57 25 4
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我尝试在套接字之间传递音频,但它在客户端中传递了一次,然后客户端停止工作。我认为我编写和发送的方式可能有误请帮助我解决此代码以下是我的服务器代码:

  public void run(){
try{
SetInitialSettings();
int bufferSize = (int) format.getSampleRate() * (int) format.getFrameSize();
System.out.println("length :" +bufferSize);
out = new ByteArrayOutputStream();
readagain=true;
while(record){
int count=0;

for(int i=0;i<1000;i++)
{

if(buffer==null){
buffer = new byte[bufferSize];
}
count = line.read(buffer, 0, buffer.length);
if (count > 0) {
//out.write(buffer, 0, count);
//readagain=false;
for (int j=0;i<ser.clientReceiver.audioSender.size();j++){
ser.clientReceiver.audioSender.get(i).cliOut.write("Audio".getBytes());
ser.clientReceiver.audioSender.get(i).cliOut.write('\n');
ser.clientReceiver.audioSender.get(i).cliOut.flush();
ser.clientReceiver.audioSender.get(i).cliOut.write(buffer,0,count);
ser.clientReceiver.audioSender.get(i).cliOut.flush();
Thread.sleep(2000);

}
}

}




}
}
catch(Exception ex)
{
System.out.println(ex.getMessage());

}




}

下面是我的客户端代码:

公共(public)无效运行(){

    try{
//audioReceiver = new TAudioReceiver(cli);
//audioReceiver.start();
while(true){

//Thread.sleep(1000);
System.out.println("reading token");
cmd= cli.BufferedReader().readLine();
System.out.println("token :" +cmd);
switch (cmd) {
case "Msg":
message = cli.BufferedReader().readLine();
cmd="None";
break;
case "File":
GetFile();
break;
case "Audio":
PlayAudio();
break;


}


}

//reading msgs here
}
catch(Exception ex)
{
//throw new InterruptedException(ex.getMessage());
}
}

这是当“音频”消息从服务器接收到客户端时需要运行的函数

 public void PlayAudio()throws Exception{

try{

cli.ServerInputStream().read(buffer);


audio = buffer;
audioIn = new ByteArrayInputStream(audio);
AudioFormat f = new AudioFormat(8000, 8, 1,true, true);
ain= new AudioInputStream(audioIn,f, audio.length/f.getFrameSize());
DataLine.Info info = new DataLine.Info(SourceDataLine.class, f);
try (SourceDataLine line = (SourceDataLine)AudioSystem.getLine(info)) {
int bufferSize = (int) f.getSampleRate()* f.getFrameSize();
buffer= new byte[bufferSize];
int count;
while ((count = ain.read(buffer, 0, buffer.length)) != -1) {
if (count > 0) {
line.write(buffer, 0, count);
}
}
line.drain();
}

}
catch(Exception ex)
{
System.out.println("file" + ex.getMessage());
}


}

最佳答案

您的原始代码更好。你必须写(缓冲区,0,计数),而不是写(缓冲区)。否则,您将在上次读取未读取的每个缓冲区的末尾写入垃圾。您的第二段代码忽略了 read() 的结果。

关于java - 如何在java中的套接字之间传递音频,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14448412/

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