bash - 将 xml 解析为并替换特定标签 shell 脚本

Question

对于下面的xml，我需要替换<studentStatus>对于 <studentName>CLASSA</studentName>至 <studentStatus>failed</studentStatus> .

<studentFile>
    <student>
        <studentName>CLASSA</studentName>
        <studentStatus>Success</studentStatus>
        <studentActions>
            <studentAction>
                <studentType>Juniour</studentType>
                <studentStatus>Completed</studentStatus>
                <studentMsg/>
            </studentAction>
            <studentAction>
                <studentType>HighSchool</studentType>
                <studentStatus>Completed</studentStatus>
                <studentMsg/>
            </studentAction>
        </studentActions>
    </student>
    <student>
        <studentName>CLASSB</studentName>
        <studentStatus>Success</studentStatus>
        <studentActions>
            <studentAction>
                <studentType>Senior</studentType>
                <studentStatus>Completed</studentStatus>
            </studentAction>
            <studentAction>
                <studentType>Middle</studentType>
                <studentStatus>Completed</studentStatus>
            </studentAction>                         
        </studentActions>
    </student>
</studentFile>

到目前为止我得到了什么，

xmllint -xpath "/studentFile/student[studentName='CLASSA']/studentActions/studentAction[studentType="Juniour"]/studentStatus" myxml.xml

现在我得到学生的状态为 Completed，现在这个值应该更改为 Failed。仅适用于 <studentType>Juniour</studentType> .我应该如何编辑 xml 才能将其作为 ,

<studentFile>
    <student>
        <studentName>CLASSA</studentName>
        <studentStatus>Success</studentStatus>
        <studentActions>
            <studentAction>
                <studentType>Juniour</studentType>
                <studentStatus>Failed</studentStatus>
                <studentMsg/>
            </studentAction>
            <studentAction>
                <studentType>HighSchool</studentType>
                <studentStatus>Completed</studentStatus>
                <studentMsg/>
            </studentAction>
        </studentActions>
    </student>
    <student>
        <studentName>CLASSB</studentName>
        <studentStatus>Success</studentStatus>
        <studentActions>
            <studentAction>
                <studentType>Senior</studentType>
                <studentStatus>Completed</studentStatus>
            </studentAction>
            <studentAction>
                <studentType>Middle</studentType>
                <studentStatus>Completed</studentStatus>
            </studentAction>                         
        </studentActions>
    </student>
</studentFile>

这可以使用 sed 来完成吗？我知道有像 xsltproc 这样的工具，但不确定它是否安装在我们集群的所有节点中。

任何帮助将不胜感激。提前致谢!

Answer 1

使用 file.xml 中的 xmllint 更新值:

xmllint --shell file.xml << EOF
cd /studentFile/student[studentName='CLASSA']/studentActions/studentAction[studentType='Juniour']/studentStatus
set failed
save
EOF

或没有here document :

echo -e "cd /studentFile/student[studentName='CLASSA']/studentActions/studentAction[studentType='Juniour']/studentStatus\nset failed\nsave" | xmllint --shell file.xml

---

更新:在变量中使用 bash 和 XML:

xml=$(xmllint --shell <(echo "$xml") << EOF
cd /studentFile/student[studentName='CLASSA']/studentActions/studentAction[studentType='Juniour']/studentStatus
set failed
save -
EOF
)

或者没有这里文档:

xml=$(echo -e "cd /studentFile/student[studentName='CLASSA']/studentActions/studentAction[studentType='Juniour']/studentStatus\nset failed\nsave -" | xmllint --shell <(echo "$xml"))