php - fatal error : Call to undefined function getsqlvaluestring()

Question

大家好，当我尝试使用默认的 Dreamweaver 登录模块登录时，我收到此错误，请帮助我 - 这是一个问题，我只是一名 html 设计师，试图为我的一个小网站制作一个简单的登录脚本我正在工作一个。如果您能提供帮助，那就太好了

    <?php require_once('../Connections/dsfsdfsdfd.php'); ?>
    <?php
    // *** Validate request to login to this site.
    if (!isset($_SESSION)) {
    session_start();
    }
    $loginFormAction = $_SERVER['PHP_SELF'];
    if (isset($_GET['accesscheck'])) {
    $_SESSION['PrevUrl'] = $_GET['accesscheck'];
    }

    if (isset($_POST['username'])) {
    $loginUsername=$_POST['username'];
    $password=$_POST['password'];
    $MM_fldUserAuthorization = "access_level";
    $MM_redirectLoginSuccess = "index.php";
    $MM_redirecttoReferrer = true;
    mysql_select_db($database_promocenter, $promocenter);

    $LoginRS__query=sprintf("SELECT username, password, destination_page FROM
    users WHERE username=%s AND password=%s",
    GetSQLValueString($loginUsername, "text"), GetSQLValueString($password, "int")); 


    $LoginRS = mysql_query($LoginRS__query, $promocenter) or die(mysql_error());
    $loginFoundUser = mysql_num_rows($LoginRS);
    if ($loginFoundUser) {

    $loginStrGroup = mysql_result($LoginRS,0,'access_level');

    if (PHP_VERSION >= 5.1) {session_regenerate_id(true);}
    else {session_regenerate_id();}
    //declare two session variables and assign them
    $_SESSION['MM_Username'] = $loginUsername;
    $_SESSION['MM_UserGroup'] = $loginStrGroup;       

    if (isset($_SESSION['PrevUrl']) && true) {
    $MM_redirectLoginSuccess = $_SESSION['PrevUrl'];    
    }
    header("Location: " . $MM_redirectLoginSuccess );
    }
    else {
    header("Location: ". $MM_redirectLoginFailed );
    }
    }
    ?>
    <?php
    if (!function_exists("GetSQLValueString")) {
    function GetSQLValueString($theValue, $theType,
    $theDefinedValue = "", $theNotDefinedValue = "") 
    {
    if (PHP_VERSION < 6) {
    $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;
    }

    $theValue = function_exists("mysql_real_escape_string") ?
    mysql_real_escape_string($theValue) : mysql_escape_string($theValue);

    switch ($theType) {
    case "text":
    $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
    break;    
    case "long":
    case "int":
    $theValue = ($theValue != "") ? intval($theValue) : "NULL";
    break;
    case "double":
    $theValue = ($theValue != "") ? doubleval($theValue) : "NULL";
    break;
    case "date":
    $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
    break;
    case "defined":
    $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
    break;
    }
    return $theValue;
    }
    }

    mysql_select_db($database_promocenter, $promocenter);
    $query_rs_users_login = "SELECT * FROM users";
    $rs_users_login = mysql_query($query_rs_users_login, $promocenter)
    or die(mysql_error());
    $row_rs_users_login = mysql_fetch_assoc($rs_users_login);
    $totalRows_rs_users_login = mysql_num_rows($rs_users_login);
    ?>

抱歉，错误是 fatal error :在第 22 行调用/u1/home/xxxxxx/public_html/newsletters/Resources/promocenter/admin/login.php 中的未定义函数 getsqlvaluestring() 这是标准的 dreamweaver cs5 代码。

连接到数据库等。我确信我的代码顶部包含该文件，请查看那里。我还可以说这段代码在一年内运行得很好，突然每次我尝试登录时都会出现此错误。正常的前端仍然显示数据库中的字段。只是/admin/登录端出现了问题

Answer 1

Fatal error: Call to undefined function getsqlvaluestring()

说明没有这个功能。我猜这个函数是另一个文件，而你忘了包含它。