bash - 使用 grep 和 cut delimiter 命令(在 bash shell 脚本 UNIX 中)- 和 "reversing"一样吗？

Question

所以我有一个包含文本的文件:

puddle2_1557936:/home/rogers.williams/folderz/puddle2

我想使用grep命令

grep puddle2_1557936

与 cut 命令(或其他命令，如果需要)混合以仅显示这一部分:

/home/rogers.williams/folderz/puddle2

到目前为止，我知道如果这样做

 grep puddle2_1557936 | cut -d ":" -f1

然后会显示

puddle2_1557936

那么有没有办法“反转”定界符剪切命令？

注意:解决方案必须从 grep puddle2_15579636 开始。

Answer 1

您无需更改分隔符即可使用 cut 显示字符串的右侧部分。

cut 命令的 -f 开关是第 n 个元素，由分隔符分隔::，因此您只需键入:

 grep puddle2_1557936 | cut -d ":" -f2

---

如果你想玩得开心，另一个解决方案(稍微调整一下):

使用 grep :

grep -oP 'puddle2_1557936:\K.*' <<< 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'                                                                        
/home/rogers.williams/folderz/puddle2

或仍使用 look around regex

grep -oP '(?<=puddle2_1557936:).*' <<< 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'                                                                    
/home/rogers.williams/folderz/puddle2

或使用 perl :

perl -lne '/puddle2_1557936:(.*)/ and print $1' <<< 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'                                                      
/home/rogers.williams/folderz/puddle2

或使用 ruby (感谢 glenn jackman)

ruby -F: -ane '/puddle2_1557936/ and puts $F[1]' <<< 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'
/home/rogers.williams/folderz/puddle2

或使用 awk :

awk -F'puddle2_1557936:' '{print $2}'  <<< 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'
/home/rogers.williams/folderz/puddle2

或使用 python :

python -c 'import sys; print(sys.argv[1].split("puddle2_1557936:")[1])' 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'
/home/rogers.williams/folderz/puddle2

或仅使用 bash :

IFS=: read _ a <<< "puddle2_1557936:/home/rogers.williams/folderz/puddle2"
echo "$a"
/home/rogers.williams/folderz/puddle2

或使用 js在shell :

js<<EOF
var x = 'puddle2_1557936:/home/rogers.williams/folderz/puddle2'
print(x.substr(x.indexOf(":")+1))
EOF
/home/rogers.williams/folderz/puddle2

或使用 php在shell :

php -r 'preg_match("/puddle2_1557936:(.*)/", $argv[1], $m); echo "$m[1]\n";' 'puddle2_1557936:/home/rogers.williams/folderz/puddle2' 
/home/rogers.williams/folderz/puddle2