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java - 一次只能播放一个声音片段

转载 作者:行者123 更新时间:2023-11-29 08:52:23 25 4
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我为我的游戏编写了一个自定义声音系统,但是如果要求在几毫秒内播放两个声音,则只会播放一个声音片段。

我试过像这样在新线程上运行回放,但没有成功。没有抛出异常,它只是不会播放两种声音。

Thread one = new Thread() {
public void run() {
try {
CustomSound.playSound(id, loop, dist);
} catch (Exception e) {
e.printStackTrace();
}
}
};

这是声音播放器类

public class CustomSound {

/*
* Directory of your sound files
* format is WAV
*/
private static final String DIRECTORY = sign.signlink.findcachedir()+"audio/effects/";

/*
* Current volume state
* 36 chosen for default 50% volume state
*/
public static float settingModifier = 70f;

/*
* Current volume state
*/
public static boolean isMuted;

/*
* Clips
*/
private static Clip[] clipIndex = null;

/*
* Get number of files in directory
*/
private static final int getDirectoryLength() {
return new File(DIRECTORY).list().length;
}

/**
* Loads the sound clips into memory
* during startup to prevent lag if loading
* them during runtime.
**/
public static void preloadSounds() {
clipIndex = new Clip[getDirectoryLength()];
int counter = 0;
for (int i = 0; i < clipIndex.length; i++) {
try {
File f = new File(DIRECTORY+"sound "+i+".wav");
AudioInputStream audioInputStream = AudioSystem.getAudioInputStream(f);
clipIndex[i] = AudioSystem.getClip();
clipIndex[i].open(audioInputStream);
counter++;
} catch (MalformedURLException e) {
System.out.println("Sound effect not found: "+i);
e.printStackTrace();
return;
} catch (UnsupportedAudioFileException e) {
System.out.println("Unsupported format for sound: "+i);
return;
} catch (LineUnavailableException e) {
e.printStackTrace();
return;
} catch (Exception e) {
e.printStackTrace();
return;
}
}
System.out.println("Succesfully loaded: "+counter+" custom sound clips.");
}

/**
* Plays a sound
* @param soundID - The ID of the sound
* @param loop - How many times to loop this sound
* @param distanceFromSource - The distance from the source in tiles
*/
public static void playSound(final int soundID, int loop, int distanceFromSource) {

try {
if (!isMuted) {
clipIndex[soundID].setFramePosition(0);
applyVolumeSetting(clipIndex[soundID], getDistanceModifier(distanceFromSource)*settingModifier);
if (loop == 1 || loop == 0) {
clipIndex[soundID].start();
} else {
clipIndex[soundID].loop(loop);
}
/* shows how to close line when clip is finished playing
clipIndex[soundID].addLineListener(new LineListener() {
public void update(LineEvent myLineEvent) {
if (myLineEvent.getType() == LineEvent.Type.STOP)
clipIndex[soundID].close();
}
});
*/
}
} catch (Exception e) {
System.out.println("Error please report: ");
e.printStackTrace();
}
}

/**
* Applies volume setting to the clip
* @param line - the Clip to adjust volume setting for
* @param volume - the volume percentage (0-100)
* @return - the volume with applied setting
*/
public static float applyVolumeSetting(Clip line, double volume) {
//System.out.println("Modifying volume to "+volume);
if (volume > 100.0) volume = 100.0;
if (volume >= 0.0) {
FloatControl ctrl = null;
try {
ctrl = (FloatControl)(line.getControl(FloatControl.Type.MASTER_GAIN));
} catch (IllegalArgumentException iax1) {
try {
ctrl = (FloatControl)(line.getControl(FloatControl.Type.VOLUME));
} catch (IllegalArgumentException iax2) {
System.out.println("Controls.setVolume() not supported.");
return -1;
}
}
float minimum = ctrl.getMinimum();
float maximum = ctrl.getMaximum();
float newValue = (float)(minimum + volume * (maximum - minimum) / 100.0F);
//System.out.println("System min: " + minimum);
//System.out.println("System max: " + maximum);
if (newValue <= ctrl.getMinimum())
newValue = ctrl.getMinimum();
if (newValue >= ctrl.getMaximum())
newValue = ctrl.getMaximum();

ctrl.setValue(newValue);
//System.out.println("Setting modifier = " + volume);
//System.out.println("New value = " + newValue);
return newValue;
}
return -1;
}

/**
* Calculates tile distance modifier
* @param tileDistance - distance in tiles from source
* @return - the distance modifier
*/
public static float getDistanceModifier(int tileDistance) {
if (tileDistance <= 0) {
tileDistance = 0;
}
if (tileDistance >= 10) {
tileDistance = 10;
}
float distanceModifier = 0;
if (tileDistance == 10)
distanceModifier = 0.40f;
if (tileDistance == 9)
distanceModifier = 0.55f;
if (tileDistance == 8)
distanceModifier = 0.60f;
if (tileDistance == 7)
distanceModifier = 0.65f;
if (tileDistance == 6)
distanceModifier = 0.70f;
if (tileDistance == 5)
distanceModifier = 0.75f;
if (tileDistance == 4)
distanceModifier = 0.80f;
if (tileDistance == 3)
distanceModifier = 0.85f;
if (tileDistance == 2)
distanceModifier = 0.90f;
if (tileDistance == 1)
distanceModifier = 0.95f;
if (tileDistance == 0)
distanceModifier = 1.00f;

return distanceModifier;
}

}

最佳答案

当我在我的 Windows 机器上测试你的代码时,我在短时间内连续播放两种不同的声音没有问题:

public static void main(String[] args) throws Exception {

CustomSound.preloadSounds();

CustomSound.playSound(0, 0, 0);
CustomSound.playSound(1, 0, 0);

Thread.sleep(5000);
}

但是请注意,DataLine#start()是一个异步调用。这可能与您的问题有关。

此外,根据 DataLine#start() 的文档,

If invoked on a line that is already running, this method does nothing.

如果这是你的问题,并且你想同时播放相同的声音两次,一个可能的解决方案是获取另一个播放相同声音的 Clip 实例并启动它。

但是我不是 Java 的声音 API 方面的专家,所以可能有更有效的方法。

关于java - 一次只能播放一个声音片段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22133333/

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