mysql - 从数据库中选择最接近的经度/纬度值

Question

我有一个包含几千个职位的数据库。这些是公交车站。我想做的是获取 LON/LAT 位置最接近值的 X 个数量。

这是我的表格的布局:

CREATE TABLE IF NOT EXISTS `buss_StopPoints` (
  `Name` varchar(50) NOT NULL,
  `LocationNorthing` varchar(30) NOT NULL,
  `LocationEasting` varchar(30) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

以下是一些示例行:

INSERT INTO `buss_StopPoints` (`Name`, `LocationNorthing`, `LocationEasting`) VALUES ('Some station', '59.3195952318672', '18.0717401337168');
INSERT INTO `buss_StopPoints` (`Name`, `LocationNorthing`, `LocationEasting`) VALUES ('Some station 2', '59.3195772927918', '18.0717389396547');
INSERT INTO `buss_StopPoints` (`Name`, `LocationNorthing`, `LocationEasting`) VALUES ('Some station 3', '59.3234014331742', '18.0671617033088');
INSERT INTO `buss_StopPoints` (`Name`, `LocationNorthing`, `LocationEasting`) VALUES ('Some station 4', '59.3233921590479', '18.0671786573678');
INSERT INTO `buss_StopPoints` (`Name`, `LocationNorthing`, `LocationEasting`) VALUES ('Some station 5', '59.3313179695727', '18.061677395945');

我的问题:如何创建一个 select 语句，从数据库中选择最接近的 X 行(无论是正向还是负向)。 (例如，假设我请求 59.3234014331742,18.0671617033088 并想要最近的 4 个车站，在这种情况下应该返回全部)。

Answer 1

LAT = latitude value
LON = longitude value

SELECT Name, (6371 * acos( cos( radians(LAT) ) * cos( radians( LocationNorthing ) ) * cos( radians( LON ) - radians(LocationEasting) ) + sin( radians(LAT) ) * sin( radians(LocationNorthing) ) )) AS distance order by distance