bash - 使用 gawk 解析 CSV 文件

Question

如何使用 gawk 解析 CSV 文件？简单地设置 FS="," 是不够的，因为内部带有逗号的引号字段将被视为多个字段。

使用 FS="," 无效的示例:

文件内容:

one,two,"three, four",five
"six, seven",eight,"nine"

gawk 脚本:

BEGIN { FS="," }
{
  for (i=1; i<=NF; i++) printf "field #%d: %s\n", i, $(i)
  printf "---------------------------\n"
}

错误的输出:

field #1: one
field #2: two
field #3: "three
field #4:  four"
field #5: five
---------------------------
field #1: "six
field #2:  seven"
field #3: eight
field #4: "nine"
---------------------------

期望的输出:

field #1: one
field #2: two
field #3: "three, four"
field #4: five
---------------------------
field #1: "six, seven"
field #2: eight
field #3: "nine"
---------------------------

Answer 1

The gawk version 4 manual说要使用 FPAT = "([^,]*)|(\"[^\"]+\")"

定义 FPAT 时，它会禁用 FS 并按内容而不是分隔符指定字段。