bash - 将 stdout 和 stderr 重定向到函数

Question

我需要帮助将输出(stdin 和 stdout)从系统命令发送到 bash 函数，同时仍然接受来自参数的输入。类似于下面的示例。有人能给我指明正确的道路吗？

LogMsg()
{
  DateTime=`date "+%Y/%m/%d %H:%M:%S"`
  echo '*****'$DateTime' ('$QMAKESPEC'): '$1 >> "$LogFile"
  echo $DateTime' ('$QMAKESPEC'): '$1
}

# Already works
LogMsg "This statement is sent directly"

# Wish I could do this:
# Capture both stdout & stderr of a system function to the logfile
# I do not presume that any of the syntax that follows is good
make 2>&1 >(LogMsg)

Answer 1

为此，您可以使用 read bash 内置:

LogMsg()
{
  read IN # This reads a string from stdin and stores it in a variable called IN
  DateTime=`date "+%Y/%m/%d %H:%M:%S"`
  echo '*****'$DateTime' ('$QMAKESPEC'): '$IN >> "$LogFile"
  echo $DateTime' ('$QMAKESPEC'): '$IN
}

然后使用管道:

make 2>&1 | LogMsg

更新:

为了能够使用标准输入或参数作为输入(根据 chepner 的评论)，您可以这样做:

LogMsg()
{
  if [ -n "$1" ]
  then
      IN="$1"
  else
      read IN # This reads a string from stdin and stores it in a variable called IN
  fi

  DateTime=`date "+%Y/%m/%d %H:%M:%S"`
  echo '*****'$DateTime' ('$QMAKESPEC'): '$IN >> "$LogFile"
  echo $DateTime' ('$QMAKESPEC'): '$IN
}