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php - 使用我的代码的表单更新 MySQL 不起作用

转载 作者:行者123 更新时间:2023-11-29 08:44:49 25 4
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我试图在这里做一些非常简单的事情。我想做的就是更新 MySQL 中的信息下面是表单的代码。

 <?php
$host=""; // Host name
$username=""; // Mysql username
$password=""; // Mysql password
$db_name=""; // Database name
$tbl_name=""; // Table name

// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

// get value of id that sent from address bar
$dj=$_GET['dj'];

// Retrieve data from database
$sql="SELECT * FROM $tbl_name WHERE dj='$dj'";
$result=mysql_query($sql);
$rows=mysql_fetch_array($result);
?>

<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<form name="form1" method="post" action="update_ac.php">
<td>
<table width="100%" border="0" cellspacing="1" cellpadding="0">
<tr>
<td>&nbsp;</td>
<td colspan="3"><strong>Update The information for the Now PlayingProgram.</strong>
</td>
</tr>
<tr>
<td align="center">&nbsp;</td>
<td align="center">&nbsp;</td>
<td align="center">&nbsp;</td>
<td align="center">&nbsp;</td>
</tr>
<tr>
<td align="center">&nbsp;</td>
<td align="center"><strong>Name</strong></td>
<td align="center"><strong>Email</strong></td>
<td align="center"><strong>Email2</strong></td>
</tr>
<tr>
<td>&nbsp;</td>
<td align="center">
<input name="name" type="text" id="name" value="<?php echo $rows['name']; ?>">
</td>
<td align="center">
<input name="email" type="text" id="email" value="<?php echo $rows['email']; ?>" size="15">
</td>
<td>
<input name="email2" type="text" id="email2" value="<?php echo $rows['email2']; ?>" size="15">
</td>
</tr>
<tr>
<td align="center">&nbsp;</td>
<td align="center"><strong>Twitter</strong></td>
<td align="center"><strong>Twitter2</strong></td>
<td align="center"><strong>Avatar</strong></td>
</tr>
<tr>
<td>&nbsp;</td>
<td align="center">
<input name="twitter" type="text" id="twitter" value="<?php echo $rows['twitter']; ?>">
</td>
<td align="center">
<input name="twitter2" type="text" id="twitter2" value="<?php echo $rows['twitter2']; ?>" size="15">
</td>
<td>
<input name="avatar" type="text" id="avatar" value="<?php echo $rows['avatar']; ?>" size="15">
</td>
</tr>
<tr>
<td align="center">&nbsp;</td>
<td align="center"><strong>Facebook</strong></td>
<td align="center"><strong>Facebook2</strong></td>
<td align="center"><strong>Type</strong></td>
</tr>
<tr>
<td>&nbsp;</td>
<td align="center">
<input name="facebook" type="text" id="facebook" value="<?php echo $rows['facebook']; ?>">
</td>
<td align="center">
<input name="facebook2" type="text" id="facebook2" value="<?php echo $rows['facebook2']; ?>" size="15">
</td>
<td>
<input name="type" type="text" id="type" value="<?php echo $rows['type']; ?>" size="15">
</td>
</tr>
<tr>
<td align="center">&nbsp;</td>
<td align="center"><strong>Alias1</strong></td>
<td align="center"><strong>Alias2</strong></td>
<td align="center"><strong>Alias3</strong></td>
</tr>
<tr>
<td>&nbsp;</td>
<td align="center">
<input name="alias1" type="text" id="alias1" value="<?php echo $rows['alias1']; ?>">
</td>
<td align="center">
<input name="alias2" type="text" id="alias2" value="<?php echo $rows['alias2']; ?>" size="15">
</td>
<td>
<input name="alias3" type="text" id="alias3" value="<?php echo $rows['alias3']; ?>" size="15">
</td>
</tr>

<tr>
<td align="center">&nbsp;</td>
<td colspan="3" align="center"><strong>Request Line</strong></td>
</tr>
<tr>
<td>&nbsp;</td>
<td colspan="3" align="center">
<input name="address" type="text" id="address" value="<?php echo $rows['address']; ?>" size="65">
</td>
</tr>
<tr>
<td>&nbsp;</td>
<td>
<input name="dj" type="hidden" id="dj" value="<?php echo $rows['dj']; ?>">
</td>
<td align="center">
<input type="submit" name="Submit" value="Submit">
</td>
<td>&nbsp;</td>
</tr>
</table>
</td>
</form>
</tr>
</table>
<?php
// close connection
mysql_close();
?>

现在我想要做的是编辑当前在表单中显示的数据库中的信息。 (该表单显示来自 mysql 的正确信息)如果我想更改电子邮件2,我只需在字段中进行更改,然后单击提交。好吧,我的问题是,当我这样做时,我得到的只是错误。

所以让我们看看我的 update_ac.php代码如下:

<?php
$host="localhost"; // Host name
$username=""; // Mysql username
$password=""; // Mysql password
$db_name=""; // Database name
$tbl_name=""; // Table name

// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

// Connect to server and select database.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

// update data in mysql database
$sql="UPDATE currentdj SET name='$name',
email='$email',
email2='$email2',
twitter='$twitter',
twitter2='$twitter2',
avatar='$avatar',
facebook='$facebook',
facebook2='$facebook2',
type='$type',
alias1='$alias1',
alias2='$alias2',
alias3='$alias3',
address='$address'
WHERE dj='$dj'";
$result=mysql_query($sql);

// if successfully updated.
if($result){
echo "Successful";
echo "<BR>";
echo "<a href='list_records.php'>View result</a>";
}

else {
echo "ERROR";
}

?>

我想知道我是否只是遇到语法问题,甚至是拼写问题!任何帮助将不胜感激。

谢谢!

最佳答案

UPDATE查询中,email字段的单引号未闭合email='$email,

"UPDATE currentdj SET  name='$name',
email='$email', //Add THE MISSING SINGLE QUOTE HERE
email2='$email2',

关于php - 使用我的代码的表单更新 MySQL 不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12774989/

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