MySQL查询通过列名选择表名

Question

我正在尝试从指定数据库中选择包含“lang”和“project”列的所有表。这就是我正在做的事情:

SELECT DISTINCT(ISC1.TABLE_NAME) AS `table` FROM INFORMATION_SCHEMA.COLUMNS AS ISC1 
JOIN INFORMATION_SCHEMA.COLUMNS AS ISC2 ON 
    (ISC1.TABLE_SCHEMA=ISC2.TABLE_SCHEMA AND ISC1.TABLE_NAME=ISC2.TABLE_NAME AND ISC2.COLUMN_NAME='project') 
WHERE ISC1.COLUMN_NAME='lang' AND ISC2.COLUMN_NAME='project' AND ISC1.TABLE_SCHEMA='some_database'

• 它确实有效，但我有一种感觉，这是编写此类查询的糟糕方法。如果有人可以改进它，那就太好了。
• 现在我必须更改此查询以选择具有“lang”列但没有“project”列的所有表。老实说，我不知道从哪里开始......

感谢您的帮助

Answer 1

SELECT DISTINCT(ISC1.TABLE_NAME) AS `table`
FROM INFORMATION_SCHEMA.COLUMNS AS ISC1,
    INFORMATION_SCHEMA.COLUMNS AS ISC2 
WHERE ISC1.TABLE_SCHEMA=ISC2.TABLE_SCHEMA
AND ISC1.TABLE_NAME=ISC2.TABLE_NAME
AND ISC2.COLUMN_NAME='project'
AND ISC1.COLUMN_NAME='lang'
AND ISC1.TABLE_SCHEMA='some_database'

没有项目栏:

SELECT DISTINCT(ISC.TABLE_NAME) AS `table`
FROM INFORMATION_SCHEMA.COLUMNS AS ISC
WHERE ISC.COLUMN_NAME='lang'
AND ISC.TABLE_SCHEMA='some_database'
AND NOT EXISTS(SELECT *
    FROM INFORMATION_SCHEMA.COLUMNS C
    WHERE C.COLUMN_NAME = 'project'
    AND C.TABLE_NAME=ISC.TABLE_NAME
    AND C.TABLE_SCHEMA=ISC.TABLE_SCHEMA)