bash - 从另一个脚本调用一个 Bash 脚本，通过引号和空格传递参数

Question

我在 Linux 上做了两个测试 bash 脚本来弄清楚问题。

TestScript1 看起来像:

    echo "TestScript1 Arguments:"
    echo "$1"
    echo "$2"
    echo "$#"
    ./testscript2 $1 $2

TestScript2 看起来像:

    echo "TestScript2 Arguments received from TestScript1:"
    echo "$1"
    echo "$2"
    echo "$#"

当我按以下方式执行testscript1时:

    ./testscript1 "Firstname Lastname" testmail@example.com

期望的输出应该是:

    TestScript1 Arguments:
    Firstname Lastname
    testmail@example.com
    2
    TestScript2 Arguments received from TestScript1:
    Firstname Lastname
    testmail@example.com
    2

但实际输出是:

    TestScript1 Arguments:
    Firstname Lastname
    testmail@example.com
    2
    TestScript2 Arguments received from TestScript1:
    Firstname
    Lastname
    3

我该如何解决这个问题？我想获得所需的输出而不是实际输出。

Answer 1

在 Testscript 1 中引用你的参数:

echo "TestScript1 Arguments:"
echo "$1"
echo "$2"
echo "$#"
./testscript2 "$1" "$2"