string - 将多行字符串中的指定列转换为单个逗号分隔行

Question

假设我有以下字符串:

something1:    +12.0   (some unnecessary trailing data (this must go))
something2:    +15.5   (some more unnecessary trailing data)
something4:    +9.0   (some other unnecessary data)
something1:    +13.5  (blah blah blah)

我怎样才能把它变成简单的

+12.0,+15.5,+9.0,+13.5

在 bash 中？

Answer 1

简洁明了:

awk '{print $2}' file.txt | paste -s -d, -