php - 将 JavaScript 确认中的值传递给 Codeigniter Controller

Question

我是 JavaScript 和 Codeigniter 新手。我想知道如何将 JavaScript 确认(是/否)传递给 Codeigniter Controller 。

例如我有一个链接

更新所有记录。(如何链接这个？)。

用户单击它后，会弹出一条消息，显示您确定吗？。如果是，那么它将被传递到 Controller /模型并进行更新，如果不是，它将保留在同一页面上。

或者有人可以教我其他方法吗？

Answer 1

你用什么？单选按钮？如果是，只需在单选按钮标签上方添加表单标签即可。

这是示例

<form name = "yesno" action = "<?php site_url('check/yesorno') ?>" method = "post">
    <input type = "radio" name = "yesorno" value = "yes" onclick = "this.form.submit()">Yes
    <br>
    <input type = "radio" name = "yesorno" value = "no" onclick = "this.form.submit">No
</form>

/*Note:
Form name = name of form
action = destionation url (site_url(yourController/yourFunction))
method = post/get
onclick = javascript event (will execute the code when user click)
this.form.submit() = javascript dom, means submit the your form when specified event executed*/

如果你想使用ajax，请编写代码

//first->create the object
//for chrome, firefox, etc
if(window.XMLHttpRequest)
{
   xmlhttp = new XMLHttpRequest();
}
//fro ie, etc
else
{
   xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}

    //to get response from php
xmlhttp.onreadystatechange = function()
{
    if(xmlhttp.readyState == 4 && xmlhttp.status == 200)
    {
    //your code here
    }
}

    //open connection
    xmlhttp.open("GET","../project_php/login.php",true);
xmlhttp.send();

/*Note:
  GET -> method
  2nd paramater(../project_php/login.php) -> destination url
  3rd parameter -> true or false (use true!)

  on "your code here" comment, add your code if response from php successfully received.
*/