bash - 如何使用 Bash 递归地创建不存在的子目录？

Question

我正在创建一个快速备份脚本，它将一些数据库转储到一个漂亮/整洁的目录结构中，我意识到我需要测试以确保在创建目录之前存在这些目录。我的代码有效，但有更好的方法吗？

[ -d "$BACKUP_DIR" ] || mkdir "$BACKUP_DIR"
[ -d "$BACKUP_DIR/$client" ] || mkdir "$BACKUP_DIR/$client"
[ -d "$BACKUP_DIR/$client/$year" ] || mkdir "$BACKUP_DIR/$client/$year"
[ -d "$BACKUP_DIR/$client/$year/$month" ] || mkdir "$BACKUP_DIR/$client/$year/$month"
[ -d "$BACKUP_DIR/$client/$year/$month/$day" ] || mkdir "$BACKUP_DIR/$client/$year/$month/$day"

Answer 1

可以使用-p参数，即documented as :

-p, --parents

no error if existing, make parent directories as needed

所以:

mkdir -p "$BACKUP_DIR/$client/$year/$month/$day"