php - 从 MySQL 中连续选择随机用户

Question

我正在努力优化查询

(从 1 个表中随机选择 2 位用户)

id  | name |  total | img
------------------------ --
1    user1   500      1
2    user2   600      2
3    user3   650      3

需要结果和 ABS(total1 -total2) < 200

id1  | id2|  name1 | name2 | img1 | img2 |  total1 | total2
------------------------ -------------------------------------
1       3    user1   user3    1      3        500      650

为了获得更高的性能，请重写以下内容:

SELECT
  C1.id AS id1, C1.img AS img1, C1.name AS name1,
  C2.id AS id2, C2.img AS img2, C2.name AS name2,
  C1.total AS total1, C2.total AS total2
FROM users C1, users C2
WHERE C1.id <> C2.id 
  AND ABS(C1.total - C2.total) < 200
ORDER BY RAND()
LIMIT 1

致

$dbh = new PDO ("mysql:host=$hostname;dbname=$dbname","$username","$pw");
$rs = $dbh->query(
"SELECT COUNT(*) AS 'count'
 FROM users C1, users C2
 WHERE C1.id <> C2.id
   AND ABS(C1.total - C2.total) < 200");
$target = rand(0,$rs[0]['count']);
$rs = $dbh->query(
  "SELECT 
   C1.id AS id1, C1.img AS img1, C1.name AS name1,
   C2.id AS id2, C2.img AS img2, C2.name AS name2,
   C1.total AS total1, C2.total AS total2
  FROM users C1, users C2
  WHERE C1.id <> C2.id
   AND ABS(C1.total - C2.total) < 200
  LIMIT ?,1",
array($target));


foreach ($rs as $row) 
                    { 
                     print $row['name1']; 
                     }

返回空结果，我错过了什么，与数据库的连接正常(另一个查询正在工作)

Answer 1

这是您的解决方案:

SELECT u1.id1, u2.id2, u1.name1, u2.name2, u1.total1, u2.total2, u1.img1, u2.img2 
FROM 
(
    SELECT u.id id1, u.name name1, u.total total1, u.img img1 
    FROM users u 
    ORDER BY RAND()
) u1
CROSS JOIN
(
    SELECT u.id id2, u.name name2, u.total total2, u.img img2 
    FROM users u 
    ORDER BY RAND()
) u2
WHERE u1.id1 != u2.id2 AND ABS(u1.total1 - u2.total2) < 200
LIMIT 0,1;

Demo