php - 从一个表中选择数据，检查并从第二个表中提取值

Question

我有一个如下所示的sql查询，它根据问题表中是否存在以及它们的section_id值落在一定范围内来选择值，

SELECT action_id, action_type, action_details, action_int, action_time
        FROM actions
        WHERE user_id = '".$id."'
        AND action_type = 'other'
        AND ( action_details = 'random question'
                OR action_details = 'review')
        AND action_int IN (
            SELECT id
            FROM questions
            WHERE section_id IN (2,3,4,5,6,7,8) )

我想扩展它以从问题表“section_id”中提取第二列值，并将其连接到结果中。

解决这个问题的最佳方法是什么？谢谢

Answer 1

根据您在section_id中使用in，我相信这个左连接应该有效:

SELECT a.action_id, a.action_type, a.action_details, a.action_int, a.action_time, q.section_id 
FROM actions a left join questions q on a.action_int = q.id 
WHERE a.user_id = '".$id."'
    AND a.action_type = 'other'
    AND a.action_details in('random question', 'review') 
    AND q.section_id IN (2,3,4,5,6,7,8);