java - 我不知道为什么这段代码会自己换行

Question

我将这段代码分为三部分；主要，DisSystem，DisIndexerUI。其目的是计算不适指数。计算系统运行完美，但我发现打印结果有问题。这是结果:

input temperature
36
input humidity
42    
Discomfort Index:96.75999999999999    
Very very uncomfortable    
It is

我觉得应该打印“It is very very uncomfortable”，但是我打印的结果是

Very very uncomfortable    
It is

这是一个非常奇怪的情况。我想知道为什么会这样。

我当然知道，如果我这样修复它:

    System.out.println("Discomfort Index:"+ ui.input());
    System.out.print("It is ");
    ui.status();

它将打印“这非常非常不舒服”。但我认为这只是一个临时解决方案。为什么会断线？

public class Main {
public static void main(String[] args) {

    double temp = 0;
    double humidity = 0;

    DisSystem dis = new DisSystem();
    DisIndexerUI ui = new DisIndexerUI(dis);

    System.out.println("Discomfort Index:"+ ui.input());
    System.out.println("It is" + ui.status());

}
}    
==================================
public class DisSystem {    

public static double Formula(double temp, double humidity) {
    double formula = 0.72 * (temp + humidity) + 40.6;
    return formula;
}

    }    
=================================
import java.util.Scanner;

public class DisIndexerUI {
DisSystem disSystem;
double formula = 0;

public DisIndexerUI(DisSystem disSystem) {
    this.disSystem = disSystem;
}

public double input() {
    Scanner scanner = new Scanner(System.in);
    System.out.println("input temperature");
    double temp = Double.parseDouble(scanner.nextLine());
    System.out.println("input humidity");
    double humidity = Double.parseDouble(scanner.nextLine());
    formula = disSystem.Formula(temp, humidity);
    return formula;
}

public String status() {
    String str = "";
    if (formula >= 86) {
        System.out.println("Very very uncomfortable");
    } else if (formula >= 83) {
        System.out.println("Very uncomfortable");
    } else if (formula >= 80) {
        System.out.println("uncomfortable");
    } else if (formula >= 75) {
        System.out.println("nomal");
    } else if (formula >= 70) {
        System.out.println("good");
    } else if (formula >= 68) {
        System.out.println("very good");
    }
    return str;

    }

}    

Answer 1

您只是在 status 方法中返回一个空字符串，但打印实际值。

public String status() {
    if (formula >= 86) {
        return "Very very uncomfortable";
    } else if (formula >= 83) {
        return "Very uncomfortable";
    } else if (formula >= 80) {
        return "uncomfortable";
    } else if (formula >= 75) {
        return "nomal";
    } else if (formula >= 70) {
        return "good";
    } else if (formula >= 68) {
        return "very good";
    } else {
        return "";
    }
}

进一步检查 else 语句中的空字符串是否适合您的用例。