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java - 使用自定义身份验证了解 spring security 中的 "Access Denied"

转载 作者:行者123 更新时间:2023-11-29 08:26:54 26 4
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我正在尝试掌握 Spring Security 和经过相当多的工作(并在 SO 上提供帮助)后,我能够在 spring security 中实现一些自定义身份验证机制,但现在我遇到了一些我不太了解的授权问题。

如果我向 localhost:8080/login?username=admin&password=sesamOeffneDich&secondSecret=youNeedMe 发出 POST 请求,我会收到 403 访问被拒绝。

如果有人能解释原因,我将不胜感激。

我的配置如下:

@Configuration
@EnableWebSecurity
@EnableWebMvc
@ComponentScan
public class AppConfig extends WebSecurityConfigurerAdapter
{
@Autowired
MyAuthenticationProvider myAuthenticationProvider;

@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.authenticationProvider(myAuthenticationProvider);
}

@Override
protected void configure(HttpSecurity http) throws Exception
{
http.addFilterBefore(new MyAuthenticationFilter(authenticationManager()), BasicAuthenticationFilter.class)
.authorizeRequests().antMatchers("/**")
.hasAnyRole()
.anyRequest()
.authenticated()
.and()
.csrf().disable()
.httpBasic().disable();
}

@Bean
public AuthenticationManager authenticationManager(){
return new ProviderManager(Arrays.asList(myAuthenticationProvider));
}

@Bean
public ViewResolver viewResolver()
{
InternalResourceViewResolver viewResolver = new InternalResourceViewResolver();
viewResolver.setPrefix("/WEB-INF/views/");
viewResolver.setSuffix(".jsp");
return viewResolver;
}
}

我认为使用此配置,授权机制会由于[...].hasAnyRole()[...] 自动授予访问权限。

这是我的 token 实现;为了练习目的,我想保持简单;如果需要理解实现的任何其他部分,请告诉我,我会提供它,但我不想一开始就用太多不必要的代码淹没帖子:

public class MyAuthenticationToken implements Authentication {
public static final String SECOND_SECRET = "youNeedMe";
private final String principalName;
private MyCredentials credentials;
private boolean authenticated;

public MyAuthenticationToken(String principalName, MyCredentials credentials) {
this.principalName = principalName;
this.credentials = credentials;
}
//Everyone is admin for the sake of the example
@Override
public Collection<? extends GrantedAuthority> getAuthorities() {
LinkedList<GrantedAuthority> authorities = new LinkedList<>();
authorities.add(new SimpleGrantedAuthority("ADMIN"));
return authorities;
}

@Override
public Object getCredentials() {
return this.credentials;
}

@Override
public Object getDetails() {
return null;
}

@Override
public Object getPrincipal() {
return this.principalName;
}

@Override
public boolean isAuthenticated() {
return this.authenticated;
}

@Override
public void setAuthenticated(boolean b) throws IllegalArgumentException {
this.authenticated = b;
}

@Override
public String getName() {
return this.principalName;
}
}

编辑:根据要求我添加更多的来源。

public class MyAuthenticationFilter extends AbstractAuthenticationProcessingFilter {

public MyAuthenticationFilter(AuthenticationManager authenticationManager) {
super(new AntPathRequestMatcher("/login", "POST"));
this.setAuthenticationManager(authenticationManager);
}

@Override
public Authentication attemptAuthentication(HttpServletRequest request, HttpServletResponse response) throws AuthenticationException {
if (!request.getMethod().equals("POST")) {
throw new AuthenticationServiceException(
"Authentication method not supported: " + request.getMethod());
}

String username = request.getParameter("username");
String password = request.getParameter("password");
String secondSecret = request.getParameter("secondSecret");

if (username == null) {
username = "";
}

if (password == null) {
password = "";
}

username = username.trim();

MyAuthenticationToken authRequest = new MyAuthenticationToken(username, new MyCredentials(password, secondSecret));

return this.getAuthenticationManager().authenticate(authRequest);
}
}

和:

@Component
public class MyAuthenticationProvider implements AuthenticationProvider {
@Override
public Authentication authenticate(Authentication authentication) throws AuthenticationException {
MyAuthenticationToken myAuthenticationToken = (MyAuthenticationToken) authentication;
MyCredentials credentials = (MyCredentials) myAuthenticationToken.getCredentials();
if (credentials.getPassword().equals("sesamOeffneDich") && credentials.getSecondSecret().equals(MyAuthenticationToken.SECOND_SECRET)){
myAuthenticationToken.setAuthenticated(true);
return myAuthenticationToken;
}else{
throw new BadCredentialsException("Bad credentials supplied!");
}
}

@Override
public boolean supports(Class<?> authentication) {
return MyAuthenticationToken.class.isAssignableFrom(authentication);
}
}

最佳答案

为了处理您的问题,我需要 MyAuthenticationFilter 和 MyAuthenticationProvider 的来源。但是我之前有一个更好的解决方案,您可以在我的 github 上找到一个完全可行的配置了自定义身份验证和 RBAC(基于角色的访问控制)授权的 spring security 示例:https://github.com/mehditahmasebi/spring/tree/master/spring-boot

希望对您有所帮助。


我的 WebConfig(或如您所说的 AppConfig)来源:

@Configuration
@EnableWebMvc
@EnableWebSecurity
@EnableGlobalMethodSecurity(
prePostEnabled=true,
securedEnabled=true,
jsr250Enabled=true)
public class WebConfig extends WebSecurityConfigurerAdapter implements WebMvcConfigurer {

@Override
protected void configure(HttpSecurity http) throws Exception {
http
.authorizeRequests()
.antMatchers("/public/**").permitAll()
.anyRequest().authenticated()
.and().csrf().disable();
}

@Override
public void addCorsMappings(CorsRegistry registry) {
registry.addMapping("/**")
.allowCredentials(true)
.allowedHeaders("*")
.allowedMethods("GET, POST, PATCH, PUT, DELETE, OPTIONS")
.allowedOrigins("*");
}

@Bean
public InternalResourceViewResolver jspViewResolver() {
InternalResourceViewResolver resolver= new InternalResourceViewResolver();
resolver.setPrefix("/jsp/");
resolver.setSuffix(".jsp");
return resolver;
}

@Bean
public ErrorPageFilter errorPageFilter() {
return new ErrorPageFilter();
}
}

和 CustomAuthentication 的来源:

@Component
public class CustomAuthenticationProvider implements AuthenticationProvider {

public CustomAuthenticationProvider() {
super();
}

// API

@Override
public Authentication authenticate(final Authentication authentication) throws AuthenticationException {
final String name = authentication.getName();
final String password = authentication.getCredentials().toString();
final List<GrantedAuthority> grantedAuths = new ArrayList<>();

if(!(name.equals("admin") && password.equals("admin")) &&
!(name.equals("user") && password.equals("user")))
throw new RuntimeException("username or password is incorrect");
if(name.equals("admin"))
{
grantedAuths.add(new SimpleGrantedAuthority("ROLE_USER"));
grantedAuths.add(new SimpleGrantedAuthority("ROLE_ADMIN"));
}
else
grantedAuths.add(new SimpleGrantedAuthority("ROLE_USER"));

final UserDetails principal = new User(name, password, grantedAuths);
final Authentication auth = new UsernamePasswordAuthenticationToken(principal, password, grantedAuths);
return auth;

}

@Override
public boolean supports(final Class<?> authentication) {
return authentication.equals(UsernamePasswordAuthenticationToken.class);
}

}

LoginService 的来源是:

@RestController
@RequestMapping("/public/login")
public class LoginService {

@Autowired
CustomAuthenticationProvider provider;

@GetMapping
public String loginTest(){
return "Login OK";
}

@GetMapping("/{username}/{password}")
public ResponseEntity<Map<String, String>> login(@PathVariable String username,@PathVariable String password ,HttpServletRequest request)
{
UsernamePasswordAuthenticationToken token = new UsernamePasswordAuthenticationToken(username, password);
Authentication authenticate = provider.authenticate(token);
SecurityContextHolder.getContext().setAuthentication(authenticate);
request.getSession().setAttribute("username", username);
Map<String, String> result = new HashMap<>();
result.put(username, new String(Base64.getEncoder().encode(password.getBytes())));
ResponseEntity<Map<String, String>> finalResult = new ResponseEntity<>(result,HttpStatus.OK);
return finalResult;
}
}

要运行项目,请下载并运行:

mvnw Spring 启动:运行

然后 --> http://localhost:8080/public/login/admin/admin

那么你会得到你想要的成功结果。

干杯。


编辑:

在添加源更新问题后,我发现了问题。

有一些解决方案:

将/** 更改为/login

    http.addFilterBefore(new MyAuthenticationFilter(authenticationManager()), BasicAuthenticationFilter.class)
.authorizeRequests()
.antMatchers("/login").hasAnyRole()
.anyRequest().authenticated()
.and()
.csrf().disable()
.httpBasic().disable();

或者以最简单的方式删除你的 antMatchers ** :

    http.addFilterBefore(new MyAuthenticationFilter(authenticationManager()), BasicAuthenticationFilter.class)
.authorizeRequests()
.anyRequest().authenticated()
.and()
.csrf().disable()
.httpBasic().disable();

实际上,如果你想要角色检查,在登录服务上检查角色不是一个好主意,最好是用户先登录,然后在进一步的请求(其他特定的 antMatcherUrl)中检查角色。

同时可以使用@Secured进行角色授权。

为了安全保证,我在登录前添加了一个 Hello 服务来确定安全异常,登录后一切正常。

@RestController("/hello")
public class HelloService {

@GetMapping
public String get()
{
return "Hello there!";
}

}

关于java - 使用自定义身份验证了解 spring security 中的 "Access Denied",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52015859/

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