rust - 如何将从 env::current_exe() 获取的文件路径转换为字符串或 str？-6ren

rust - 如何将从 env::current_exe() 获取的文件路径转换为字符串或 str？

转载作者：行者123 更新时间：2023-11-29 08:26:17

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在获取可执行文件的文件路径并在 inner_main() 中附加 nvs 之后，我尝试在 main() 中将其转换为字符串:

use std::{env, io, path::PathBuf, process};

fn inner_main() -> io::Result<PathBuf> {
    let exe = env::current_exe()?;
    let dir = exe.parent().expect("Executable must be in some directory");
    let dir = dir.join("nvs");
    Ok(dir)
}

fn main() {
    let path = inner_main() as String;
    println!("The current directory is {:?}", path);
    process::exit(0);
}

它会导致错误:

error[E0605]: non-primitive cast: `std::result::Result<std::path::PathBuf, std::io::Error>` as `std::string::String`
  --> src/main.rs:11:16
   |
11 |     let path = inner_main() as String;
   |                ^^^^^^^^^^^^^^^^^^^^^^
   |
   = note: an `as` expression can only be used to convert between primitive types. Consider using the `From` trait

我该如何将其转换为 String 或 &str？