rust - 如何获得两个整数的底商？

Question

我有两个 u64，我想将它们分开并讨论结果。 (因为它们是无符号的，所以 floor 和 round to zero 是相同的。)

我该怎么做？

Answer 1

impl Div<i32> for i32文档说:

This operation rounds towards zero, truncating any fractional part of the exact result.

它适用于所有整数类型:

macro_rules! div_impl_integer {
    ($($t:ty)*) => ($(
        /// This operation rounds towards zero, truncating any
        /// fractional part of the exact result.
        #[stable(feature = "rust1", since = "1.0.0")]
        impl Div for $t {
            type Output = $t;

            #[inline]
            fn div(self, other: $t) -> $t { self / other }
        }

        forward_ref_binop! { impl Div, div for $t, $t }
    )*)
}

div_impl_integer! { usize u8 u16 u32 u64 u128 isize i8 i16 i32 i64 i128 }

因此，您需要做的就是正常划分。

assert_eq!(3/2, 1);
assert_eq!(9/4, 2);