java - 如何在 Java 中验证电话号码(美国格式)？

Question

我只想知道我哪里错了:

import java.io.*;


    class Tokens{   
            public static void main(String[] args)
            {
               //String[] result = "this is a test".split("");

                String[] result = "4543 6546 6556".split("");
                boolean flag= true;         

                String num[] = {"0","1","2","3","4","5","6","7","8","9"};
                String specialChars[] = {"-","@","#","*"," "};


                for (int x=1; x<result.length; x++)
                {   
                    for (int y=0; y<num.length; y++)
                    {
                        if ((result[x].equals(num[y])))
                        {
                            flag = false;
                            continue;

                        }
                        else
                        {
                            flag = true;
                        }


                        if (flag == true)
                        break;

                    }   

                if (flag == false)
                break;

                }           

                System.out.println(flag);

            }

    }

Answer 1

如果这不是家庭作业，您是否有理由避免使用正则表达式？

这里有一些有用的:http://regexlib.com/DisplayPatterns.aspx?cattabindex=6&categoryId=7

更一般地说，您的代码似乎无法验证您是否有电话号码，它似乎只是验证您的字符串是否仅由数字组成。您现在也不允许使用任何特殊字符。