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php - 从我的 MySQL 表检查登录信息

转载 作者:行者123 更新时间:2023-11-29 08:16:37 25 4
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我这里有代码检查我的 MySQL 表的登录信息,然后我希望继续我的 session ,但它似乎不起作用。

这段代码正在检查我的登录,它是 check_login.php

 <?php

$host="localhost"; // Host name
$username="root"; // Mysql username
$password=""; // Mysql password
$db_name="student"; // Database name
$tbl_name="login"; // Table name

// Connect to server and select database.
mysql_connect("$host", "$username", "$password", "$db_name")or die("cannot connect1");
mysql_select_db("$db_name")or die("cannot select DB");

// username and password sent from form
$myusername=$_POST['myusername'];
$mypassword=$_POST['mypassword'];

// To protect MySQL injection (more detail about MySQL injection)
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$myusername = mysql_real_escape_string($myusername);
$mypassword = mysql_real_escape_string($mypassword);
$sql="SELECT * FROM $tbl_name WHERE Username='$myusername' and Password='$mypassword'";
//$sqlaccesslevel="SELECT AccessLevel FROM $tbl_name WHERE Username='$myusername' and Password='$mypassword'";
$result = mysql_query($sql) or die(mysql_error());
//$resultaccesslevel = mysql_query($sqlaccesslevel) or die(mysql_error());

// Mysql_num_row is counting table row
if ($result)
$count=mysql_num_rows($result);
else
$count = 0;

// If result matched $myusername and $mypassword, table row must be 1 row
if($count==1){
// Register $myusername, $mypassword and redirect to the website"
session_start();
$_SESSION['username'] = "$username";


header("location:student.html");
}
else {
echo "Wrong Username or Password. YOU LOOSE. GOOD DAY SIR.";
}


?>

这是我的login.html页面,当用户输入详细信息时会发布到我的check_login.php

  <html>
<head>
</head>
<body>
<table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<form name="form1" method="post" action="check_login.php">
<td>
<table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF">
<tr>
<td colspan="3"><strong>Student Login</strong></td>
</tr>
<tr>
<td width="78">Username</td>
<td width="6">:</td>
<td width="294"><input name="myusername" type="text" id="myusername"></td>
</tr>
<tr>
<td>Password</td>
<td>:</td>
<td><input name="mypassword" type="text" id="mypassword"></td>
</tr>
<tr>
<td>&nbsp;</td>
<td>&nbsp;</td>
<td><input type="submit" name="Submit" value="Login"></td>
</tr>
</table>
</td>
</form>
</tr>
</table>
</body>
</html>

我将其输出到student.html,登录似乎可以正常工作,但 session 没有提供任何帮助,非常感谢。

<html>
<head>
</head>
<body>


<h1>hello
</h1>

<?php // this starts the session
session_start();
if( isset($_SESSION["sessionusername"]) )
{
header("location:student.html");
}
// echo variable from the session, we set this on our other page
echo "Welcome":
echo $_SESSION['user'];
?>





</body>
</html>

最佳答案

session_start(); 放在您的 php 文件顶部,同时 read this topicthis这是关于在 php 和配置指令中使用 session 。

关于php - 从我的 MySQL 表检查登录信息,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20492140/

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