rust - 如何将字符串与静态 &str 匹配？

Question

我正在编写一个程序，它在字符串处理方面可能做的有点多。我将大部分文字消息移至常量；我不确定这是否是 Rust 中的正确方法，但我习惯于用 C 编写。

我发现我不能轻易地在 match 表达式中使用我的 static &str 。我可以使用文本本身，但不知道如何正确地使用它。

我知道这是一个编译器问题，但不知道如何以 Rust 风格正确地编写该构造​​。我应该使用枚举而不是类 C 的静态变量吗？

static SECTION_TEST: &str = "test result:";
static STATUS_TEST_OK: &str = "PASSED";

fn match_out(out: &String) -> bool {
    let s = &out[out.find(SECTION_TEST).unwrap() + SECTION_TEST.len()..];

    match s {
        STATUS_TEST_OK => {
            println!("Yes");
            true
        }
        _ => {
            println!("No");
            false
        }
    }
}

error[E0530]: match bindings cannot shadow statics
 --> src/lib.rs:8:9
  |
2 | static STATUS_TEST_OK: &str = "PASSED";
  | --------------------------------------- the static `STATUS_TEST_OK` is defined here
...
8 |         STATUS_TEST_OK => {
  |         ^^^^^^^^^^^^^^ cannot be named the same as a static

Answer 1

使用 constant 而不是 static:

const STATUS_TEST_OK: &str = "PASSED";

fn match_out(s: &str) -> bool {
    match s {
        STATUS_TEST_OK => {
            println!("Yes");
            true
        }
        _ => {
            println!("No");
            false
        }
    }
}

另见:

• What is the difference between a const variable and a static variable and which should I choose?
• What is the difference between immutable and const variables in Rust?
• How to match a String against string literals in Rust?
• Why is this match pattern unreachable when using non-literal patterns?