php - 使用 PHP 计算年月存档中的内容

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我需要打印每年/月的新闻数量，如下所示:

2013

• 十月 (20)
• 十一月 (45)
• 九月(80)

2014

• 一月 (5)

我有这个:

 $sql = "SELECT YEAR(FROM_UNIXTIME(timestamp)) AS YEAR, 
                MONTHNAME(FROM_UNIXTIME(timestamp)) AS MONTH, 
                COUNT(*) AS TOTAL 
         FROM NEWS GROUP BY YEAR, MONTH";
 $newsdata = DataAccess::ArrayFetch($sql);

 foreach($newsdata AS $news){            
   //what???   
 }

现在，如何打印年份和月份？

Answer 1

您在查询中对它们进行排序，然后按该顺序打印它们。您需要检测年份更改，以打印年份标题:

$sql = "SELECT YEAR(FROM_UNIXTIME(timestamp)) AS YEAR, 
                MONTHNAME(FROM_UNIXTIME(timestamp)) AS MONTH, 
                COUNT(*) AS TOTAL 
         FROM NEWS GROUP BY YEAR, MONTH ORDER BY YEAR DESC, MONTH ";
$newsdata = DataAccess::ArrayFetch($sql);

$currentYear = null;

foreach($newsdata AS $news){            
  if ($currentYear != $news['YEAR']){
    echo '<h2>'.$news['YEAR'].'<h2>';
    $currentYear = $news['YEAR'];
  } 
  echo '<dd>'.$news['MONTH'].'<dd><dt>'.$news['TOTAL'].'</dt>';
}