rust - &mut [T] 的 slice_mut

Question

为什么 MutableSlice::slice_mut没有为 &mut [T] 实现吗？

在 rustc 0.12.0-nightly (b2d4eb186 2014-10-02 15:57:19 +0000) 上测试:

fn sort<T>(v: &mut [T]){
    let (l, r) = v.split_at_mut(2); // Ok
    let len = v.slice_mut(1u, 3u).len(); // error: type `&mut [T]` does not implement any method in scope named `slice_mut`
}

#[test]
fn it_works() {
    let mut v = [1i, 2, 3, 4, 5, 6];
    sort(v);
}

Answer 1

那个方法had been removed , 但是 the change has since been rolled back . sort 函数的第二行 compiles right now .