java - 无法从线程启动 Activity

Question

我无法从线程开始 Activity 。我想在 2 秒后开始一项 Activity 。但它给出错误 - 应用程序意外停止。

这是我要从中运行线程的 Activity 的代码。

package com.pack.prog;

import android.app.Activity;
import android.content.Intent;
import android.media.MediaPlayer;
import android.os.Bundle;
import android.view.Window;
import android.view.WindowManager.LayoutParams;
import android.widget.Toast;

public class Splash extends Activity {

    MediaPlayer mPlayer;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        try {
            super.onCreate(savedInstanceState);
            requestWindowFeature(Window.FEATURE_NO_TITLE);
            getWindow().setFlags(LayoutParams.FLAG_FULLSCREEN,
                    LayoutParams.FLAG_FULLSCREEN);

            setContentView(R.layout.splash);

            mPlayer = MediaPlayer.create(Splash.this, R.raw.happy_moments);
            mPlayer.start();

            Thread thread = new Thread() {
                public void run() {

                    try {
                        sleep(2000);
                    } catch (Exception e) {
                        // TODO Auto-generated catch block
                        Toast.makeText(Splash.this, e.toString(),
                                Toast.LENGTH_LONG).show();
                    } finally {
                        Intent i = new Intent("com.pack.prog.StartingMenu");
                        startActivity(i);
                    }

                };
            };
            thread.start();

        } catch (Exception e) {
            Toast.makeText(this, e.toString(), Toast.LENGTH_LONG).show();
        }
    }

    @Override
    protected void onPause() {

        try {
            super.onPause();
            if (mPlayer.isPlaying()) {
                mPlayer.release();
            }
        } catch (Exception e) {
            // TODO Auto-generated catch block
            Toast.makeText(this, e.toString(), Toast.LENGTH_LONG).show();
        }
    }

    @Override
    public void onBackPressed() {
        try {
            super.onBackPressed();
            if (mPlayer.isPlaying()) {
                mPlayer.release();
            }
        } catch (Exception w) {
            Toast.makeText(this, w.toString(), Toast.LENGTH_LONG).show();
        } finally {
            finish();
        }
    }

}

这是 list 文件。

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.pack.prog"
    android:versionCode="1"
    android:versionName="1.0" >

    <uses-sdk android:minSdkVersion="10" />

    <application
        android:icon="@drawable/ic_launcher"
        android:label="@string/app_name" >
        <activity
            android:name=".Splash"
            android:label="@string/app_name" >
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />

                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>

        <activity
            android:name=".StartingMenu"
            android:label="@string/app_name" >
            <intent-filter>
                <action android:name="com.pack.prog.STARTINGMENU" />

                <category android:name="android.intent.category.DEFAULT" />
            </intent-filter>
        </activity>


    </application>

</manifest>

我认为只有 list 有问题。

Answer 1

我认为操作名称不同于 "com.pack.prog.StartingMenu" 和 list "com.pack.prog.STARTINGMENU"

并且还在 UI 线程中执行此操作 .....

  mPlayer = MediaPlayer.create(Splash.this, R.raw.happy_moments);
  mPlayer.start();
new Handler().postDelayed(new Runnable() {

                public void run() {

                    Intent i = new Intent("com.pack.prog.STARTINGMENU"); //<--- what ever which is right
                    startActivity(i); 
                }
            }, 2000);