gpt4 book ai didi

php - 无法使用 PHP INSERT INTO 数据库,没有抛出错误

转载 作者:行者123 更新时间:2023-11-29 07:57:07 25 4
gpt4 key购买 nike

好吧,我正在使用 PHP,我需要将文本框的内容放入数据库的表中,当我单击“提交”时,不会抛出错误,但数据库中不会放入任何内容,这是我的代码:

HTML:

<html>
<title>Chat App</title>
<head>
<link rel="stylesheet" type="text/css" href="chatCSS.css">
</head>
<body>
<div class="logOut">
<form action="loggedOut.php" method="POST">
<input type="submit" value="Log Out">
</form>
</div>
<div class="incomeMessages">
<input type="text" id="incomeMessageBox" disabled="disabled">
<br>
<br>
<form method="POST" action="index.php">
<input type="text" name="message" id="myMessage" placeholder="Message here...">
<input type="submit" id="myMessageSubmit">
</form>
</div>
</body>
</html>

PHP:

<?php
require 'includes/connect_mysql.php';
require 'includes/sessionCheck.php';

if ($_SERVER['REQUEST_METHOD'] == 'POST') {
$message = $_POST['message'];
$time = time();
$user = $_SESSION['activeUser'];

if ($db_connect) {
$SQL = "INSERT INTO mainconversation (Name, Message, Time) VALUES ('$user', '$message', '$time')";

$result = mysqli_query($connection, $SQL);
mysqli_close($connection);
}

}

?>

连接代码:

<?PHP

$db_host = "localhost";

$db_username = "xxxx";

$db_pass = "xxxxxxxx";

$db_name = "chatapp";


$connection = mysqli_connect("$db_host","$db_username","$db_pass") or die ("could not connect to mysql");
$db_connect = mysqli_select_db($connection, "$db_name") or die ("no database");

?>

最佳答案

您没有检查错误,请尝试更改您的 $result 行,如下所示:

$result = mysqli_query($connection,$SQL) or die(mysqli_error($connection));

如果有错误,您将会收到错误。

关于php - 无法使用 PHP INSERT INTO 数据库,没有抛出错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24871929/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com