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macros - 生成具有由宏确定的参数的函数的宏

转载 作者:行者123 更新时间:2023-11-29 07:56:43 25 4
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是否可以编写一个宏来生成一个函数,其中该函数的参数数量由宏决定?例如,我想写一些东西来简化在 Cassandra 驱动程序中使用准备好的语句。

let prepared = prepare!(session, "insert into blah (id, name, reading ) values (?, ?, ?)", int, string, float);
let stmt = prepared(1, "test".to_string(), 3.1);
session.execute(stmt);

prepare! 需要生成如下内容(为简洁起见,仅在此处展开​​):

fn some_func(arg1, arg2, arg3) -> Statement {
let mut statement = Statement::new("insert into blah (id, name, reading ) values (?, ?, ?)", 3);
statement.bind_int(0, arg1).unwrap()
.bind_string(1, arg2).unwrap()
.bind_float(2, arg3).unwrap()
}

最佳答案

Rust 宏中的两个难题:计数和唯一标识符。你两者都有。再一次,我是写答案的人,所以我想现在是的问题了。至少您没有询问有关解析字符串的问题(如果没有编译器插件,这是完全不可能的)。

另一个不可能的事情是将类型映射到不同的方法。你就是做不到。相反,我将假设存在执行此映射的辅助特征。

此外,Rust 没有intstring float。我假设您指的是 i32Stringf32

最后,您编写调用和扩展的方式并没有真正融合。我不明白为什么要涉及 session;它没有在扩展中使用。所以我要冒昧地假装你不需要它;如果这样做,则必须将其重新入侵。

所以,有了这个,这就是我想出的。

// Some dummy types so the following will type-check.

struct Statement;

impl Statement {
fn new(stmt: &str, args: usize) -> Self { Statement }
fn bind_int(self, pos: usize, value: i32) -> Result<Self, ()> { Ok(self) }
fn bind_float(self, pos: usize, value: f32) -> Result<Self, ()> { Ok(self) }
fn bind_string(self, pos: usize, value: String) -> Result<Self, ()> { Ok(self) }
}

struct Session;

impl Session {
fn execute(&self, stmt: Statement) {}
}

// The supporting `BindArgument` trait.

trait BindArgument {
fn bind(stmt: Statement, pos: usize, value: Self) -> Statement;
}

impl BindArgument for i32 {
fn bind(stmt: Statement, pos: usize, value: Self) -> Statement {
stmt.bind_int(pos, value).unwrap()
}
}

impl BindArgument for f32 {
fn bind(stmt: Statement, pos: usize, value: Self) -> Statement {
stmt.bind_float(pos, value).unwrap()
}
}

impl BindArgument for String {
fn bind(stmt: Statement, pos: usize, value: Self) -> Statement {
stmt.bind_string(pos, value).unwrap()
}
}

// The macro itself.

macro_rules! prepare {
// These three are taken straight from
// https://danielkeep.github.io/tlborm/book/
(@as_expr $e:expr) => {$e};

(@count_tts $($tts:tt)*) => {
<[()]>::len(&[$(prepare!(@replace_tt $tts ())),*])
};

(@replace_tt $_tt:tt $e:expr) => {$e};

// This is how we bind *one* argument.

(@bind_arg $stmt:expr, $args:expr, $pos:tt, $t:ty) => {
prepare!(@as_expr <$t as BindArgument>::bind($stmt, $pos, $args.$pos))
};

// This is how we bind *N* arguments. Note that because you can't do
// arithmetic in macros, we have to spell out every supported integer.
// This could *maybe* be factored down with some more work, but that
// can be homework. ;)

(@bind_args $stmt:expr, $args:expr, 0, $next:ty, $($tys:ty,)*) => {
prepare!(@bind_args prepare!(@bind_arg $stmt, $args, 0, $next), $args, 1, $($tys,)*)
};

(@bind_args $stmt:expr, $args:expr, 1, $next:ty, $($tys:ty,)*) => {
prepare!(@bind_args prepare!(@bind_arg $stmt, $args, 1, $next), $args, 2, $($tys,)*)
};

(@bind_args $stmt:expr, $args:expr, 2, $next:ty, $($tys:ty,)*) => {
prepare!(@bind_args prepare!(@bind_arg $stmt, $args, 2, $next), $args, 3, $($tys,)*)
};

(@bind_args $stmt:expr, $_args:expr, $_pos:tt,) => {
$stmt
};

// Finally, the entry point of the macro.

($stmt:expr, $($tys:ty),* $(,)*) => {
{
// I cheated: rather than face the horror of trying to *also* do
// unique identifiers, I just shoved the arguments into a tuple, so
// that I could just re-use the position.
fn prepared_statement(args: ($($tys,)*)) -> Statement {
let statement = Statement::new(
$stmt,
prepare!(@count_tts $(($tys))*));
prepare!(@bind_args statement, args, 0, $($tys,)*)
}
prepared_statement
}
};
}

fn main() {
let session = Session;
let prepared = prepare!(
r#"insert into blah (id, name, reading ) values (?, ?, ?)"#,
i32, String, f32);
// Don't use .to_string() for &str -> String; it's horribly inefficient.
let stmt = prepared((1, "test".to_owned(), 3.1));
session.execute(stmt);
}

下面是 main 函数的扩展,为您提供一个引用框架:

fn main() {
let session = Session;
let prepared = {
fn prepared_statement(args: (i32, String, f32)) -> Statement {
let statement = Statement::new(
r#"insert into blah (id, name, reading ) values (?, ?, ?)"#,
<[()]>::len(&[(), (), ()]));
<f32 as BindArgument>::bind(
<String as BindArgument>::bind(
<i32 as BindArgument>::bind(
statement, 0, args.0),
1, args.1),
2, args.2)
}
prepared_statement
};
// Don't use .to_string() for &str -> String; it's horribly inefficient.
let stmt = prepared((1, "test".to_owned(), 3.1));
session.execute(stmt);
}

关于macros - 生成具有由宏确定的参数的函数的宏,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33173235/

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