Java If语句数组地址

Question

我有一个代码，可以使用用户输入为我提供数组中某些点的坐标。如果数组中的数字不存在，我将添加什么代码以使代码输出显示无法找到地址？我很确定我需要一个 else 语句，但我无法让它工作。这是我现在拥有的代码。

import java.util.Scanner;

public class LabActivityArray 
{
    public static void main (String[] args) 
    {
        Scanner scanner = new Scanner (System.in); 
        int rows; 
        int columns;
        int check1,check2;

        System.out.println("Enter number of rows: "); 

        rows = scanner.nextInt(); 

        System.out.println ("Now enter the number of columns: "); 

        columns = scanner.nextInt(); 

        int[][] array = new int[rows][columns]; 

        System.out.println("Enter the number to start the array: ");

        int value = scanner.nextInt(); 
        for (int i = 0; i < rows; i++)
        {
            for (int j = 0; j < columns; j++)
            {
                array[i][j]=value++;
                System.out.print(array[i][j] + "   " ); 
            }    
            System.out.println();
        }

        System.out.println("Please give one integer value to be checked in the array: "); 
        check1 = scanner.nextInt(); 

        System.out.println ("Please give a second integer value to be checked in the array: "); 

        check2 = scanner.nextInt(); 

        for ( int i = 0; i < rows; ++i ) 
        {
            for ( int j = 0; j < columns; ++j ) 
            {
                if ( array[i][j] == check1 ) 
                {
                    System.out.print(array[i][j] + " is located at address array[" + i + "," + j + "]");       
                }
                if ( array[i][j] == check2 ) 
                {
                    System.out.print("\n" + array[i][j] + " is located at address array[" + i + "," + j + "]");
                    System.out.println(); 
                }
            }
        }
    }       
}

Answer 1

第 1 步:制作一面旗帜说

boolean check1Found = false;

第 2 步:如果找到该值，则将标志设置为 true

if ( array[i][j] == check1 ) 
{
    System.out.print(array[i][j] + " is located at address array[" + i + "," + j + "]"); 
    check1Found = true;     
}

第 3 步:循环完成后，如果该标志仍为 false

，则打印一条消息

if(check1Found == false)
{
    System.out.println("check 1 not found");
}