rust - 如何创建一个字符串而不是将其打印到标准输出？

Question

考虑以下函数:

use std::io;

pub fn hello() {
    println!("Hello, How are you doing? What's your characters name?");

    let mut name = String::new();

    io::stdin().read_line(&mut name).expect("Failed to read name. What was that name again?");

    println!("Welcome to the castle {}", name);
}

我如何获取最后一个 println! 并将其转换为 "Welcome to the caSTLe {}".to_string(); 并让 { 替换为 name(显然我需要将 -> String 添加到函数声明中。)

Answer 1

使用 format!宏。

pub fn hello() -> String {
    println!("Hello, How are you doing? What's your characters name?");

    let mut name = String::new();

    io::stdin().read_line(&mut name).expect("Failed to read name. What was that name again?");

    format!("Welcome to the castle {}", name)
}