php - MySQL 查询用于高级搜索多个条件

Question

我正在执行高级搜索查询，用户可以根据多个条件选择复选框。我是一个初学者，所以我希望我能知道我是否走在正确的道路上。我知道查询非常困惑。

编辑:我意识到这需要是两个问题，因此我将其修改为严格的查询问题

表格数据

Table ss_users
user_id  first_name   last_name   admin_level   user_approved  
1        nick         jones       0             1      
2        johnny       rocket      0             1      

Table ss_user_profile_status
user_id  photo_uploaded   
1        1
2        1

Table ss_user_photos
photo_id  user_id  filename      selected
1         1        photo_1.jpg   1
2         2        photo_2.jpg   0
3         2        photo_2.jpg   1

Table ss_general
user_id  city        state      zip     neighborhood
1        baltimore   maryland   00125   hamsterdam
2        lakeland    maine      11542   treemont

Table ss_languages
user_id  french  german  italian  spanish
1        0       1       0        1
2        0       0       1        1

Table ss_experience
user_id  waldorf  kumon  homeschooling 
1        0       1       0
2        0       0       1

我当前的结果都是用户，不应该是这样的:

SELECT 
    ss_users.*, ss_user_profile_status.*, ss_user_photos.*, ss_general.*, 
    ss_languages.*, ss_experience.*, ss_users.user_id AS userID, 
    ss_user_profile_status.user_id, ss_languages.user_id AS langID
FROM 
    ss_users
JOIN 
    ss_user_profile_status ON ss_users.user_id = ss_user_profile_status.user_id
LEFT JOIN 
    ss_user_photos ON ss_users.user_id = ss_user_photos.user_id
AND 
    ss_user_photos.selected = 1
LEFT JOIN 
    ss_languages ON ss_users.user_id = ss_languages.user_id
LEFT JOIN 
    ss_general ON ss_users.user_id = ss_general.user_id
LEFT JOIN 
    ss_experience ON ss_users.user_id = ss_experience.user_id
WHERE 
    ss_users.user_id = ss_user_profile_status.user_id 
AND 
    ss_general.neighborhood_select LIKE '%hamsterdam%'
OR 
    ss_languages.spanish = 1
OR 
    ss_experience.kumon = 1
AND 
    ss_users.sitter_approved = 1
AND 
    ss_users.admin_level = 0
GROUP BY 
    ss_users.user_id DESC

对于输出，我需要表示大部分用户配置文件，这就是我选择大量表数据以及额外联接的原因。

Answer 1

为您提供丰富的 SQL 选择

SELECT 
    ss_users.*, ss_user_profile_status.*, ss_user_photos.*, ss_general.*, 
    ss_languages.*, ss_experience.*, ss_users.user_id AS userID, 
    ss_user_profile_status.user_id, ss_languages.user_id AS langID
FROM ss_users
    JOIN ss_user_profile_status ON ss_users.user_id = ss_user_profile_status.user_id
    LEFT JOIN ss_user_photos ON ss_users.user_id = ss_user_photos.user_id AND ss_user_photos.selected = 1
    LEFT JOIN ss_languages ON ss_users.user_id = ss_languages.user_id
    LEFT JOIN ss_general ON ss_users.user_id = ss_general.user_id
    LEFT JOIN ss_experience ON ss_users.user_id = ss_experience.user_id
WHERE 
    ( ss_general.neighborhood_select LIKE '%hamsterdam%' OR ss_languages.spanish = 1 OR ss_experience.kumon = 1 ) AND ss_users.sitter_approved = 1 AND ss_users.admin_level = 0

我只编辑了几个地方，例如在 OR 周围添加括号并删除第一个条件，因为它看起来多余，并且还删除了分组依据，因为它会遗漏一些数据