Java - 词频

Question

我在 Eclipse 中创建了一个 Java 程序。该程序计算每个单词的频率。例如，如果用户输入“I went to the shop”，程序将产生输出“1 1 1 2”，即 1 个字长 1 ('I') 1 个字长 2 ('to') 1 个字长度为 3('the')和 2 个长度为 4 的词('went'，'shop')。

这些是我得到的结果。我不希望显示带有 0 的输出。我怎样才能隐藏这些并且只显示 1,2,3,4,5 的结果。

The cat sat on the mat
words[1]=0
words[2]=1
words[3]=5
words[4]=0
words[5]=0


  import java.util.Scanner;
 import java.io.*;

 public class mallinson_Liam_8
{

 public static void main(String[] args) throws Exception
 {

    Scanner scan = new Scanner(new File("body.txt"));

    while(scan.hasNext())
    {

        String s;
        s = scan.nextLine();
        String input = s;
        String strippedInput = input.replaceAll("\\W", " ");

        System.out.println("" + strippedInput);

        String[] strings = strippedInput.split(" ");
        int[] counts = new int[6];
        int total = 0;
        String text = null;

            for (String str : strings)
                if (str.length() < counts.length)
                    counts[str.length()] += 1;
            for (String s1 : strings)
                total += s1.length();   

            for (int i = 1; i < counts.length; i++){  
                System.out.println("words["+ i + "]="+counts[i]);
        StringBuilder sb = new StringBuilder(i).append(i + " letter words: ");
            for (int j = 1; j <= counts[i]; j++) {




    }}}}}

Answer 1

我知道您要求使用 Java，但为了比较，下面是我在 Scala 中的做法:

val s = "I went to the shop"
val sizes = s.split("\\W+").groupBy(_.length).mapValues(_.size)
// sizes = Map(2 -> 1, 4 -> 2, 1 -> 1, 3 -> 1)

val sortedSizes = sizes.toSeq.sorted.map(_._2)
// sortedSizes = ArrayBuffer(1, 1, 1, 2)

println(sortedSizes.mkString(" "))
// outputs: 1 1 1 2