java - Hibernate 或 HQL 选择另一个 SELECT 的结果

Question

有没有办法在以下查询中使用 HQL？


SELECT userId, pwd, pwdDate FROM
(SELECT userId, AES_DECRYPT(pwd, 'key_str') as pwd, pwdDate
FROM UserHistory order by pwdDate desc limit 5 ) AS A
WHERE pwd = :pwd


以下有效。


SELECT *
FROM UserHistory order by pwdDate desc limit 5


上面的sql在hibernate中可以是下面的


Criteria criteria = session.createCriteria(UserHistory.class);
criteria.addOrder(Order.desc("pwdDate"));
List<UserHistory> list = criteria.setMaxResults(5).list();

Answer 1

以下工作。关键是为 Native SQL 创建 SQLQuery。

String SQL = 
"SELECT A.* FROM \n" +
"(select * \n" +
" from user_history$ order by pwdDate desc limit 5 ) AS A \n" + 
"where pwd = AES_ENCRYPT(:pwd, 'key_str') \n";

Query query = session.createSQLQuery(SQL);
query.setParameter("pwd", psw);
List<UserHistory> list = query.list();