java - Android Activity 不会从弹出菜单开始

Question

我想从弹出菜单中打开一个新 Activity Make_a_contact。我确定问题只与下面的代码有关，因为当我取消注释下面的代码时 - Toast.makeText 等...(并删除我想要修复的代码)它工作正常。

感谢您的帮助!

public void Show_Settings(View v) {
//this is the settings button, whose onclick is identified in menu_thisisatest.xml
    PopupMenu popup = new PopupMenu(this, v);
    MenuInflater inflater = popup.getMenuInflater();
    inflater.inflate(R.menu.menu_thisisatest, popup.getMenu());
    popup.setOnMenuItemClickListener(new PopupMenu.OnMenuItemClickListener() {
        Intent intent = new Intent(this, Make_a_contact.class);
        return true;
//            @Override
//            public boolean onMenuItemClick(MenuItem item) {
//                Toast.makeText(getApplicationContext(),item.toString(),Toast.LENGTH_SHORT).show();
//            return true;
//        }
    });
    popup.show();
}

Answer 1

您需要在生成 Intent 后开始新的 Activity。试试打电话

startActivity(intent);

当然，您需要将该代码包含在 onMenuItemClick() 方法中，该方法目前在您的代码中已被注释掉，即

@Override
public boolean onMenuItemClick(MenuItem item) {
    Intent intent = new Intent(this, Make_a_contact.class);
    startActivity(intent);
    return true;
}